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Chris
I think your interpretation is correct, except that the line
R = M - 2.326 * Sd should be
R = M + 2.326 * SD
The minus 1 just removes the value to the left of the decimal in the
division. For example, if C = 35.00 and Ref(C,-1) = 34.75, then C /
Ref(c,-1) is 1.00719. Subtracting 1 leaves you with .00719 - the
percentage difference between the 2 values.
Also I don't understand the "*1" at the end of Stop. Why bother.
You also mentioned something about Ln of the price change. I don't
see this in the code anywhere. Are you sure the MS code is accurate,
and complete? The Stop values produced by this code is about 3 times
the close - something seems wrong
Rick
--- In amibroker@xxxxxxxxxxxxxxx, kris45mar <kris45mar@xxxx> wrote:
> Hi Group:
>
> Can anyone give me a steer in the right direction with
> this Metastock code, please?
>
> Designed to be a volatility based stop, based on Stdev
> of the Ln of the percent price change.
>
> M:= Mov(((C/Ref(C,-1))-1),14,E);
> SD:= Stdev(((C/Ref(C,-1))-1),14);
> R:= M+(2.326)*(SD);
> {R at 2.326 will give a 99% confidence rating}
> C*Exp(R)*1;
>
> Here is what I have so far:
>
> x = c/ref(c,-1) ; // what is the ((C/Ref(C,-1))-1)
> part of the MS code. Is this the value for yesterday?
>
> M = ema(x,14);
> Sd = stdev( x,14);
> R = M - 2.326 * sd;
> Stop = C * exp( R ) * 1; is this correct for AB?
>
> Regards
>
> ChrisB
>
>
>
>
> __________________________________
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