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Linearray needs set points rather than array values
try lastvalue or selectedvalue
Plot ( LineArray ( LastValue(XP0), LastValue(YP0), LastValue(XP1),
LastValue(YP1) ), "", 4, 1 );
On 6/7/05, Quad Rate Serial Abby <quad_pumped_abby@xxxxxxxxx> wrote:
> I have the following code. I am trying to normalize the price and
> plot the line of the slope of the average price over the last 15 days.
> This way I can turn it into an explore and use it to see which stocks
> are out performing relatively. I don't really need to plot the slope
> and I could take it out, but I would like to know why it doesn't work,
> because I suspect it may cause an error in the calculation of the
> array itself. If I take out the normalization division there is no
> problem. The error in the "Plot LineArray" is:
>
> Argument #4 has incorrect type (the function expects different
> argument type here)
>
> The code is:
>
> StartP = 15;
> EndP = 1;
> Price_Array = MA (( H + L ) / 2, 1 );
> LP1 = LastValue ( Cum ( 1 ));
> XP0 = LP1 - StartP;
> XP1 = LP1 - EndP;
> Base_Normalization = Ref ((( H + L ) / 2), -StartP );
> YP0 = Price_Array [ XP0 ] / Base_Normalization;
> YP1 = Price_Array [ XP1 ] / Base_Normalization;
> Plot ( Price_Array, "", 1, 1 );
> Plot ( LineArray ( XP0, YP0, XP1, YP1 ), "", 4, 1 );
>
> Thanks in advance for anybodys help,
>
> Bret
>
>
>
>
>
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>
> To get support from AmiBroker please send an e-mail directly to
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>
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--
Cheers
Graham
http://e-wire.net.au/~eb_kavan/
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