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Tomasz Janeczko wrote:
>That's simple. Use looping.
>
>K = 0;
>
>for( i = 6; i < BarCount; i++ )
>{
> K[ i ] = C[ i ] + 0.98 * K[ i - 6 ];
>}
>
>
>
Thank you, Tomasz. Obviously, I was trying to avoid a procedure I have
not yet mastered. Just as obviously, it's time I figured out how to use
what is clearly a powerful tool.
Best regards,
Owen
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