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OK DT, i agree to let this be the concluding post on this topic; we must be
boring people.
For some reason our thoughts cannot synchronize. Judging by the yellow dot
it appears that your Ct is not on the same bar as the crossings. In my
problem the predicted Ct has a reasonable value (you can see this when you
run my iterative code) for each and every bar and in fact produces a very
smooth (imo useful) indicator. btw, Using the param() allows you to analyze
any bar which, imho, is much easier than looking for real data to provide
suitable conditions.
For now a direct solution for my problem remains illusive but, since i think
it has real applications, I expect that it will be solved on this list at
some future time - given time things usually are. For now I shall have to
resort to interative methods.
thanks DT, for the interesting exchange,
herman
-----Original Message-----
From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@xxxxxxxxx]
Sent: Thursday, October 28, 2004 5:16 AM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] Re: DT's Ct prediction for the Ti3
Herman,
As I wrote, I have nothing more to add.
In every problem there is a question and many ways to answer.
Your question is : If the next bar Ti3 [the so called Ti3t] is equal
to Ref(Ti3,-3), then calculate the proper next bar close [the Ct].
It is an application to the scenario III.
Plot(C,Date()+", C",colorBlack,8);
p=5;s=0.7;f=2/(p+1);R=1-f;
e1=EMA(C,p);
e2=EMA(e1,p);
e3=EMA(e2,p);
e4=EMA(e3,p);
e5=EMA(e4,p);
e6=EMA(e5,p);
C1=-s^3;
C2=3*s^2*(1+s);
C3=-3*s*(s+1)^2;
C4=(1+s)^3;
Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
Plot(Ti3,"Ti3",colorWhite,1);
Ti3t=Ref(Ti3,-3);//the condition
Plot(Ti3t,"Ti3t...",colorRed,8);
//the calculation
Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
(f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
(f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
Plot(Ct,"Ct...",5,8);
PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);
In CSCO EOD charts I see a yellow circle on 23/12/2003.
Let us see the interpretation. I read Ct=23.87.
The next bar Ti3 is Ti3=23.93, ie the Ti3 value of 18/12/2004 .
The next bar Close [24/12/2004] is exactly C=23.87 wich match to
the "predicted" price.
I see another yellow circle on 17/11/2004.
I read Ct=21.75, which is the expected tomorrows Close. It will make
the 18/11 Ti3 equal to the 12/11 Ti3.
It is true, because
Ti3 for 12/11=22.49
Ti3 for 18/11=22.49 and
C for 18/11=21.73
Note also that the last [verification] line
PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);
will create a yellow circle when the real next bar close Ref(C,1) is
almost equal to the calculated Ct.
The only reason for this 0.02 accuracy is to see some circles.
Some conditions are quite artificial and if we ask, for example, Ti3t
to be exactly equal to Ref(Ti3,-3), it is not sure we will find any
solution.
[You should increase it to abs(Ct-Ref(C,1))<1 to begin finding yellow
circles for ^NDX]
This is all about the problem.
The code gives an analytic answer to your question and I have no
doubt we will agree.
Dimitris
PS: [you may igore it since your question is already solved]
Now, on the other side, your description speaks for another problem.
You wrote
" ...change the Close to the point where the two Ti3s (Red and
Black) cross,
at this point the C (Black)should be equal to the predicted Ct (Green
should meet Black)..."
This is a strange description.
Some points :
a. there are no Red and Black Ti3 s
b. Ct is THE CALCULATED NEXT BAR Close [for today], C is simply the
TODAYS Close and there is no obvious relation between them.
etc
These things do not match to the initial question and introduce
confusion.
In general, there are many descriptive ways to try a problem. Not all
of them will give the exact [mathematical] solution. On the other
side, the exact solution may not satisfy all these descriptive
attempts.
There are, for example, many Egyptian/Babylonian/Chineese attempts
for the Pythagorean theorem. One of them was really fascinating [and
I love it !!]: They were carefully wrote in earthen tables the weight
of the wheat produced in an orthogonal triangle wheatfield. Every
year, for many years. They were comparing this average with other,
rectangular fields !! They came too close to the Pythagorean
relation, but, the way they were thinking made the final attempt
impossible.
We do not know HOW Pythagoras came to his superb theorem. His
predecessors did not say/write anything at all.
[He was the last student of a mystic school and the first teacher of
an open forum, because HE decided to give the secret knowledge to the
people]
Samos was producing excellent wine [and it still does] and olive oil,
not so much wheat as Egypt or Babylon.
We know that his solution was valid for 2500 years, until the non-
Euclidean spaces began to appear. 2500 years is not bad at all for
the evolution of the human thought.
I think that you should stay tuned to the initial question and avoid
the various descritpive approaches, some of them may be wrong.
--- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
<psytek@xxxx> wrote:
> Dt, you are going to shoot me...but we are so close that i take
that risk!
> Making a slight change to your code I added a Param() to modify the
close
> and I changed the Ref(C,-3) to Ref(Ti3,-3) - no significant changes
thus.
> Now click on any bar and change the Close to the point where the
two Ti3s
> (Red and Black) cross, at this point the C (Black)should be equal
to the
> predicted Ct (Green should meet Black). It does not. Can you
explain where i
> went wrong?
>
> many thanks again,
> herman
>
> PriceOffSet = Param("Price offset",0,-2,2,0.001);
> BarNum = SelectedValue(BarIndex());CursorBar = BarNum == BarIndex();
> ParamPrice = C + PriceOffSet;C = IIf(CursorBar, ParamPrice, C);
> Plot(C,Date()+", C",colorBlack,8);
> p=5;s=0.7;f=2/(p+1);R=1-f;
> e1=EMA(C,p);
> e2=EMA(e1,p);
> e3=EMA(e2,p);
> e4=EMA(e3,p);
> e5=EMA(e4,p);
> e6=EMA(e5,p);
> C1=-s^3;
> C2=3*s^2*(1+s);
> C3=-3*s*(s+1)^2;
> C4=(1+s)^3;
> Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> Plot(Ti3,"Ti3",colorWhite,1);
> Ti3t=Ref(Ti3,-3);//the condition
> Plot(Ti3t,"Ti3t...",colorRed,8);
> //the calculation
> Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
> (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> Plot(Ct,"Ct...",5,8);
> PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);
>
> -----Original Message-----
> From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> Sent: Wednesday, October 27, 2004 8:16 AM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: DT's Ct prediction for the Ti3
>
>
>
> Scenario III
> If the next bar Ti3 should be equal to the Close 3 bars ago, then
> calculate the next bar Close Ct.
>
> We shall work again the scenario II formula, since we know Ti3t and
> we ask for Ct.
>
> Plot(C,Date()+", C",colorBlack,8);
> p=5;s=0.7;f=2/(p+1);R=1-f;
> e1=EMA(C,p);
> e2=EMA(e1,p);
> e3=EMA(e2,p);
> e4=EMA(e3,p);
> e5=EMA(e4,p);
> e6=EMA(e5,p);
> C1=-s^3;
> C2=3*s^2*(1+s);
> C3=-3*s*(s+1)^2;
> C4=(1+s)^3;
> Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> Plot(Ti3,"Ti3",colorWhite,1);
> Ti3t=Ref(C,-3);//the condition
> Plot(Ti3t,"Ti3t...",colorRed,8);
> //the calculation
> Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
> (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> Plot(Ct,"Ct...",5,8);
> PlotShapes(shapeCircle*(abs(Ct-Ref(C,1))<0.02),colorYellow);
>
> In CSCO chart I see a yellow circle on Feb3, 2004.
> For this date we read Ct=24.06, Ti3t=25.96.It means : If the next
bar
> Close is 24.06, then the next bar Ti3 will be equal to 25.96.
> The next bar close was indeed 24.08 and the next bar Ti3 was 25.96
> I hope it is clear, I have nothing more to add.
> Dimitris
> --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
<TSOKAKIS@xxxx>
> wrote:
> >
> > Until then, let us see how it works.
> >
> > Scenario I:
> > If the next bar CSCO close is 19, calculate the next bar Ti3.
> >
> > Plot(C,Date()+", C",colorBlack,8);
> > p=5;s=0.7;f=2/(p+1);R=1-f;
> > e1=EMA(C,p);
> > e2=EMA(e1,p);
> > e3=EMA(e2,p);
> > e4=EMA(e3,p);
> > e5=EMA(e4,p);
> > e6=EMA(e5,p);
> > C1=-s^3;
> > C2=3*s^2*(1+s);
> > C3=-3*s*(s+1)^2;
> > C4=(1+s)^3;
> > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> > Plot(Ti3,"Ti3",colorWhite,1);
> > Ct=19;//the next bar Close condition
> > Plot(Ct,"Ct",colorBrightGreen,8);
> > //the next bar Ti3 calculation
> > Ti3t=(C1*f^6+C2*f^5+C3*f^4+C4*f^3)*Ct+
> > (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+
(c1*f^4+c2*f^3+c3*f^2+c4*f)
> > *e2+(c1*f^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+(c1*f+c2*1)
> > *e5+c1*e6);
> > Plot(Ti3t,"Ti3t...",colorRed,8);
> >
> > On Aug17, for example, we read Ti3t=18.26
> > On the next bar, Aug18, the actual close is C=18.99 and the Ti3 is
> > indeed 18.26
> >
> > Scenario II
> > If the next CSCO bar Ti3 is 19, then calculate the next bar close.
> >
> > Plot(C,Date()+", C",colorBlack,8);
> > p=5;s=0.7;f=2/(p+1);R=1-f;
> > e1=EMA(C,p);
> > e2=EMA(e1,p);
> > e3=EMA(e2,p);
> > e4=EMA(e3,p);
> > e5=EMA(e4,p);
> > e6=EMA(e5,p);
> > C1=-s^3;
> > C2=3*s^2*(1+s);
> > C3=-3*s*(s+1)^2;
> > C4=(1+s)^3;
> > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> > Plot(Ti3,"Ti3",colorWhite,1);
> > Ti3t=19;//the next bar Ti3 condition
> > Plot(Ti3t,"Ti3t...",colorRed,8);
> > //the next bar Ct calculation
> > Ct=(Ti3t-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> > (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)+c4*
> > (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > Plot(Ct,"Ct...",colorbrightgreen,8);
> >
> > On Oct07 we see that we need a next bar Ct=18.75, in order to have
> a
> > next bar Ti3t=19.
> > On the next bar, Oct8, C=18.78 and Ti3=19.00
> >
> > Dimitris
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
> <TSOKAKIS@xxxx>
> > wrote:
> > >
> > > Herman,
> > > Athens would not be a bad idea.
> > > 28 Celsius now [20min before 12:00], it will be around 30 some h
> > > later.
> > > The menu is broiled fresh fish and will be served 4h later.
> > > Since the fisher and the broiler is the same person, the
> > word "fresh"
> > > is guaranteed.
> > > 10-year red wine will be also available [unlimited quantity and
> > free
> > > of charge].
> > > It would be, perhaps, the ideal condition to discuss Ti3
details.
> > > Although this message looks [strongly] into the future, it is
not
> > > dangerous as the zig functions.
> > > Dimitris
> > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
> > > <psytek@xxxx> wrote:
> > > > DT, your patience is much appreciated, it is 4:00 am here so
> I'll
> > > get some
> > > > sleep first and will study your formulas in the (later)
> morning,
> > > thanks for
> > > > the extra explanations, I think they will help. i have a
strong
> > gut
> > > feeling
> > > > your formulas really give me what i want - I may just be a
bit
> > > overwhelmed
> > > > by all the terms, they look a bit intimidating :-)
> > > >
> > > > Thanks again DT, I sure will enjoy working on it later.
> > > > herman
> > > > -----Original Message-----
> > > > From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > > > Sent: Wednesday, October 27, 2004 3:13 AM
> > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> > > >
> > > >
> > > >
> > > > Herman,
> > > > Do not add this "NOT when the Ct crosses anything", it makes
> > > things
> > > > complicated without reason. No Ct touch was used in the
> > > >
http://finance.groups.yahoo.com/group/amibroker/message/72276
> > > > solution.
> > > > Ct is the [unconditional] next bar Close, as already
> explained.
> > > > Ti3Ct is the [unconditional] next bar Ti3C.
> > > > The formulas
> > > >
> > > > Ti3Ct=(C1*f^6+C2*f^5+C3*f^4+C4*f^3)*Ct+
> > > > (1-f)*((c1*f^5+c2*f^4+c3*f^3+c4*f^2)*e1+
> > > (c1*f^4+c2*f^3+c3*f^2+c4*f)
> > > > *e2+(c1*f^3+c2*f^2+c3*f+c4*1)*e3+(c1*f^2+c2*f+c3*1)*e4+
> > (c1*f+c2*1)
> > > > *e5+c1*e6);
> > > > and
> > > > Ct=(Ti3Ct-R*(c1*(f^5*e1+f^4*e2+f^3*e3+f^2*e4+f*e5+e6)+c2*
> > > > (f^4*e1+f^3*e2+f^2*e3+f*e4+e5)+c3*(f^3*e1+f^2*e2+f*e3+e4)
+c4*
> > > > (f^2*e1+f*e2+e3)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > > >
> > > > are nothing but mathematical definitions.
> > > > The first gives the Ti3Ct as a function of Ct.Give a value
to
> > Ct
> > > and
> > > > you will get the Ti3Ct.
> > > > The second gives the Ct as a function of Ti3Ct. Give a value
> to
> > > Ti3Ct
> > > > and you will get Ct.
> > > > See also the verification in
> > > >
http://finance.groups.yahoo.com/group/amibroker/message/72290
> > > > Dimitris
> > > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den Bergen"
> > > > <psytek@xxxx> wrote:
> > > > > Thank you DT,
> > > > >
> > > > > The problem is different. We need to know the value of
> > > tomorrow's
> > > > Ct when
> > > > > two OTHER arrays cross, NOT when the Ct crosses anything:
> Ct
> > is
> > > not
> > > > required
> > > > > to touch any line. I do not know how to explain it better:
> the
> > > > objective is
> > > > > to know at what value of Ct the other two functions cross,
> > i.e.
> > > > find Ct when
> > > > > a F1(Ct) touches F2(Ref(Array,-1)). This is probably a
more
> > > useful
> > > > > application than having the raw C touch any line because
> the
> > C
> > > is
> > > > subject to
> > > > > a lot of noise and would give many false signals. I think
> > your
> > > > innovative
> > > > > math functions provide the solution for this problem but i
> > can't
> > > > figure out
> > > > > how, I hoped my code would illustrated the problem more
> > > clearly...
> > > > Forgive
> > > > > me if i am just plain dumb and the solution is staring at
> me.
> > > > >
> > > > > Anyway, thanks very much for your time DT,
> > > > > best regards,
> > > > > herman.
> > > > >
> > > > >
> > > > >
> > > > > -----Original Message-----
> > > > > From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > > > > Sent: Tuesday, October 26, 2004 2:08 AM
> > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > Subject: [amibroker] Re: DT's Ct prediction for the Ti3
> > > > >
> > > > >
> > > > >
> > > > > Herman,
> > > > > The formula is correct and gives the next bar close Ct
as
> a
> > > > function
> > > > > of tomorrow´s Ti3Ct.
> > > > > When Ti3Ct value is known [or equal to another function]
> > then
> > > Ct
> > > > is
> > > > > calculated.
> > > > > For a simple verification, set
> > > > > Ti3Ct=Ref(Ti3C,1);
> > > > > and then Ct will be EXACTLY the Ref(C,1).
> > > > >
> > > > > Plot(C,"C",colorBlack,1);
> > > > > periods=5;s=0.7;f=2/(periods+1);R=1-f;
> > > > > //the Ti3C
> > > > > price=C;
> > > > > e1C=EMA(price,periods);
> > > > > e2C=EMA(e1C,Periods);
> > > > > e3C=EMA(e2C,Periods);
> > > > > e4C=EMA(e3C,Periods);
> > > > > e5C=EMA(e4C,Periods);
> > > > > e6C=EMA(e5C,Periods);
> > > > > c1=-s*s*s;
> > > > > c2=3*s*s+3*s*s*s;
> > > > > c3=-6*s*s-3*s-3*s*s*s;
> > > > > c4=1+3*s+s*s*s+3*s*s;
> > > > > Ti3C=c1*e6C+c2*e5C+c3*e4C+c4*e3C;
> > > > > Ti3Ct=Ref(Ti3C,1);// condition
> > > > > //the Ct as a function of Ti3Ct
> > > > > Ct=(Ti3Ct-R*(c1*
> (f^5*e1C+f^4*e2C+f^3*e3C+f^2*e4C+f*e5C+e6C)
> > > +c2*
> > > > > (f^4*e1C+f^3*e2C+f^2*e3C+f*e4C+e5C)+c3*
> > > (f^3*e1C+f^2*e2C+f*e3C+e4C)
> > > > +c4*
> > > > > (f^2*e1C+f*e2C+e3C)))/(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > > > > Plot(Ref(Ct,-1),"Ct",colorRed,8);
> > > > >
> > > > > Dimitris
> > > > >
> > > > >
> > > > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den
Bergen"
> > > > > <psytek@xxxx> wrote:
> > > > > > Hello DT,
> > > > > >
> > > > > > I really appreciate your help with this however is
that
> > your
> > > > > solution looks
> > > > > > somewhat the same but isn't accurate...perhaps you
> > > misunderstood
> > > > > and are
> > > > > > calculating something else...
> > > > > >
> > > > > > The best way for me to illustrate my need is with a
> > generic
> > > > > iterative
> > > > > > solution. Sorry to impose on you DT but to see how the
> > > result
> > > > > differs you
> > > > > > have to display both your solution and mine. When you
> have
> > > > loaded
> > > > > the demo
> > > > > > code below, click on any bar and open the Param()
> window.
> > > Then
> > > > > apply an
> > > > > > offset to the selected close price until you see the
> two
> > T3s
> > > > (white
> > > > > and
> > > > > > black) cross, at that point the C price is exactly on
> the
> > > > Predicted
> > > > > Close
> > > > > > price (Red). This is not the case with your formula.
> Note
> > > that I
> > > > > moved the
> > > > > > Red predicted value forward one bar to allow easier
> > > comparison
> > > > to
> > > > > the Close
> > > > > > and show a little square when the target is hit. The
key
> > > > > requirement of
> > > > > > course it that C falls exactly on the predicted value
> > when
> > > the
> > > > T3s
> > > > > cross -
> > > > > > this doesn't happen with your indicator.
> > > > > >
> > > > > > With EOD data and restricting the calculation to the
> > display
> > > > area
> > > > > only, my
> > > > > > solutions works OK, but i need a continuous indicator
> for
> > > the
> > > > > entire data RT
> > > > > > history, this means about 100K bars. If your formula
> > worked
> > > it
> > > > > would enable
> > > > > > me to do that!!!
> > > > > >
> > > > > > Any change of making your solution match mine?
> > > > > >
> > > > > > thanks again DT,
> > > > > > herman.
> > > > > >
> > > > > >
> > > > > > ------------------------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > --------
> > > > > > ----
> > > > > >
> > > > > > SetBarsRequired(1000000,1000000);
> > > > > >
> > > > > > function Ti3(array,p,s)
> > > > > > {
> > > > > > f=2/(p+1);
> > > > > > e1=EMA(array,p);
> > > > > > e2=EMA(e1,p);
> > > > > > e3=EMA(e2,p);
> > > > > > e4=EMA(e3,p);
> > > > > > e5=EMA(e4,p);
> > > > > > e6=EMA(e5,p);
> > > > > > c1=-s*s*s;
> > > > > > c2=3*s*s+3*s*s*s;
> > > > > > c3=-6*s*s-3*s-3*s*s*s;
> > > > > > c4=1+3*s+s*s*s+3*s*s;
> > > > > > T3=c1*e6+c2*e5+c3*e4+c4*e3;
> > > > > > return T3;
> > > > > > }
> > > > > >
> > > > > > function ReferenceFunction( ReferenceArray )
> > > > > > {
> > > > > > global T3Periods, T3Sensitivity, ResetReference;
> > > > > > R = Ti3( ReferenceArray, T3Periods ,T3Sensitivity);
> > > > > > return R;
> > > > > > }
> > > > > >
> > > > > > function TestFunction( TestArray )
> > > > > > {
> > > > > > global T3Periods, T3Sensitivity, ResetReference;
> > > > > > R = Ti3( TestArray, T3Periods ,T3Sensitivity);
> > > > > > return R;
> > > > > > }
> > > > > >
> > > > > > function GetTriggerPrice( ReferenceArray, TestArray,
> > > TestBarNum,
> > > > > T3Period,
> > > > > > T3Sensitivity )
> > > > > > {
> > > > > > Precision = 0.0001;
> > > > > >
> > > > > > RefArray = ReferenceFunction( ReferenceArray );
> > > > > > RefValue = RefArray[TestBarNum ];
> > > > > >
> > > > > > TestValue = TestArray[TestBarNum];
> > > > > > TestIncr = TestValue/3;
> > > > > >
> > > > > > do {
> > > > > > TestArray[TestBarNum ] = TestValue;
> > > > > > T3t = TestFunction( TestArray);
> > > > > > TodaysT3 = T3t[TestBarNum ];
> > > > > > if( abs(TodaysT3-RefValue) < Precision );
> > > > > > else if(TodaysT3< RefValue) TestValue= TestValue+
> > > TestIncr ;
> > > > > > else TestValue= TestValue- TestIncr ;
> > > > > > TestIncr = TestIncr /2;
> > > > > > Error = abs(TodaysT3- RefValue);
> > > > > > } while ( Error > Precision );
> > > > > >
> > > > > > return TestArray[TestBarNum ];
> > > > > > }
> > > > > >
> > > > > > PriceOffSet = Param("Price offset",0,-2,2,0.001);
> > > > > > BarNum = SelectedValue(BarIndex());
> > > > > > CursorBar = BarNum == BarIndex();
> > > > > > ParamPrice = C + PriceOffSet;
> > > > > > C = IIf(CursorBar, ParamPrice, C);
> > > > > > ReferenceArray = Ref(H,-1);
> > > > > > TestArray = C;
> > > > > > T3Periods = 3;
> > > > > > T3Sensitivity = 0.7;
> > > > > >
> > > > > > FirstVisibleBar = Status( "FirstVisibleBar");
> > > > > > Lastvisiblebar = Status("LastVisibleBar");
> > > > > > TP=Null;
> > > > > > for( b = Firstvisiblebar; b < Lastvisiblebar AND b <
> > > BarCount;
> > > > b++)
> > > > > > {
> > > > > > TP[b] = GetTriggerPrice( ReferenceArray, TestArray,
b,
> > > > T3Periods,
> > > > > > T3Sensitivity );
> > > > > > }
> > > > > >
> > > > > > TargetHit = IIf(abs(C-TP) < 0.01,1,Null);
> > > > > > Plot(C,"C",1,128);
> > > > > > Plot(Ti3( ReferenceArray,
> > > > > T3Periods ,T3Sensitivity),"ReferenceArray",1,1);
> > > > > > Plot(Ti3( TestArray,
> > > T3Periods ,T3Sensitivity),"TestArray",2,1);
> > > > > > PlotShapes(TargetHit*shapeHollowSquare,9,0,TP,0);
> > > > > > Plot(TP,"TP",4,1);
> > > > > >
> > > > > > ------------------------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > --------
> > > > > > ----
> > > > > >
> > > > > >
> > > > > >
> > > > > >
> > > > > >
> > > > > > -----Original Message-----
> > > > > > From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > > > > > Sent: Monday, October 25, 2004 3:04 PM
> > > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > > Subject: [amibroker] Re: DT's Ct prediction for the
> Ti3
> > > > > >
> > > > > >
> > > > > >
> > > > > > Herman,
> > > > > > As I wrote in previous post, Ct is a function of
> Ti3Ct
> > > [and
> > > > vice
> > > > > > versa]
> > > > > > In your example, Ti3C and Ti3H should be calculated
> > > > separately, to
> > > > > > avoid any confusion.
> > > > > > The expected next bar Close Ct would be
> > > > > >
> > > > > > Plot(C,"C",colorBlack,8);
> > > > > > periods=5;s=0.7;f=2/(periods+1);R=1-f;
> > > > > > //the Ti3H
> > > > > > price=H;
> > > > > > e1H=EMA(price,periods);
> > > > > > e2H=EMA(e1H,Periods);
> > > > > > e3H=EMA(e2H,Periods);
> > > > > > e4H=EMA(e3H,Periods);
> > > > > > e5H=EMA(e4H,Periods);
> > > > > > e6H=EMA(e5H,Periods);
> > > > > > c1=-s*s*s;
> > > > > > c2=3*s*s+3*s*s*s;
> > > > > > c3=-6*s*s-3*s-3*s*s*s;
> > > > > > c4=1+3*s+s*s*s+3*s*s;
> > > > > > Ti3H=c1*e6H+c2*e5H+c3*e4H+c4*e3H;
> > > > > > //Plot(Ti3H,"Ti3H",1,1);
> > > > > > //the Ti3C
> > > > > > price=C;
> > > > > > e1C=EMA(price,periods);
> > > > > > e2C=EMA(e1C,Periods);
> > > > > > e3C=EMA(e2C,Periods);
> > > > > > e4C=EMA(e3C,Periods);
> > > > > > e5C=EMA(e4C,Periods);
> > > > > > e6C=EMA(e5C,Periods);
> > > > > > Ti3C=c1*e6C+c2*e5C+c3*e4C+c4*e3C;
> > > > > > //Plot(Ti3C,"Ti3C",2,1);
> > > > > > Ti3Ct=Ti3H;//your condition:the next bar Ti3C is
> equal
> > to
> > > > todays
> > > > > Ti3H
> > > > > > //the Ct as a function of Ti3Ct
> > > > > > Ct=(Ti3Ct-R*(c1*
> > > (f^5*e1C+f^4*e2C+f^3*e3C+f^2*e4C+f*e5C+e6C)
> > > > +c2*
> > > > > > (f^4*e1C+f^3*e2C+f^2*e3C+f*e4C+e5C)+c3*
> > > > (f^3*e1C+f^2*e2C+f*e3C+e4C)
> > > > > +c4*
> > > > > > (f^2*e1C+f*e2C+e3C)))/
(C1*f^6+C2*f^5+C3*f^4+C4*f^3) ;
> > > > > > Plot(Ct,"Ct",colorRed,8);
> > > > > >
> > > > > > For periods>10 the condition is quite rare.
> > > > > > Dimitris
> > > > > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van den
> > Bergen"
> > > > > > <psytek@xxxx> wrote:
> > > > > > > In my requirements there is only one unknown, the
> > next
> > > day
> > > > Ct as
> > > > > > the other
> > > > > > > Ti3 was using the previous bar's value. The
> equation
> > is
> > > > > solvable by
> > > > > > > iteration however it is too slow for Real Time
> data,
> > > where
> > > > in a
> > > > > > backtests i
> > > > > > > want to process 100,000 bars. The problem could
> also
> > be
> > > > stated,
> > > > > > since both
> > > > > > > Ti3s have the same value when crossing, and
> assigning
> > > > arbitrary
> > > > > > familiar
> > > > > > > price arrays to Array1 and Array2, as:
> > > > > > >
> > > > > > > Ti3( ref(H,-1), period, sensitivity ) = Ti3( C,
> > > period,
> > > > > > sensitivity )
> > > > > > >
> > > > > > > and solving for C. In this equation C is the only
> > > unknown
> > > > > because H
> > > > > > is
> > > > > > > yesterday's known value. Your earlier solutions
are
> > > close to
> > > > > this
> > > > > > but i
> > > > > > > haven't been able to modify them to this
> requirement.
> > > Note
> > > > that
> > > > > > periods and
> > > > > > > sensitivities are the same on both sides of the
> > > equation.
> > > > > > >
> > > > > > > Best regards,
> > > > > > > herman
> > > > > > >
> > > > > > >
> > > > > > > -----Original Message-----
> > > > > > > From: DIMITRIS TSOKAKIS [mailto:TSOKAKIS@x...]
> > > > > > > Sent: Monday, October 25, 2004 6:58 AM
> > > > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > > > Subject: [amibroker] Re: DT's Ct prediction for
> the
> > > Ti3
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > To be more specific:
> > > > > > > Ti3t, the next bar Ti3 of an array, is ALWAYS a
> > > [known]
> > > > > function
> > > > > > of
> > > > > > > the next bar array value arrayt.
> > > > > > > Arrayt is NOT ALWAYS a [known] function of the
> next
> > > bar
> > > > Close
> > > > > Ct.
> > > > > > > Dimitris
> > > > > > > PS : If you could be more specific about array1,
> > > array2 we
> > > > > could
> > > > > > > probably come to some result...
> > > > > > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman van
den
> > > Bergen"
> > > > > > > <psytek@xxxx> wrote:
> > > > > > > > Thank you Dt.
> > > > > > > >
> > > > > > > > herman
> > > > > > > > -----Original Message-----
> > > > > > > > From: DIMITRIS TSOKAKIS
[mailto:TSOKAKIS@x...]
> > > > > > > > Sent: Monday, October 25, 2004 6:41 AM
> > > > > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > > > > Subject: [amibroker] Re: DT's Ct prediction
> for
> > > the
> > > > Ti3
> > > > > > > >
> > > > > > > >
> > > > > > > >
> > > > > > > > Herman,
> > > > > > > > There is no answer for this general
question.
> > > > > > > > Some arrays may be RevEnged [RSI, Ti3], some
> > > others
> > > > not
> > > > > > [StochD].
> > > > > > > > The next bar RSI is a function of the next
> bar
> > > Close
> > > > Ct,
> > > > > the
> > > > > > next
> > > > > > > bar
> > > > > > > > StochD is [unfortunately] a function of Ht,
> Lt
> > > and Ct.
> > > > > > > > Dimitris
> > > > > > > > --- In amibroker@xxxxxxxxxxxxxxx, "Herman
van
> > den
> > > > Bergen"
> > > > > > > > <psytek@xxxx> wrote:
> > > > > > > > > Thank you DT, I tried this code but it
> > requires
> > > > that pb
> > > > > is
> > > > > > > greater
> > > > > > > > than pa
> > > > > > > > > and also it uses C in both Ti3s. I am
> looking
> > > for a
> > > > > sulution
> > > > > > > where
> > > > > > > > pa==pb
> > > > > > > > > and we use different price arrays.
> > > > > > > > >
> > > > > > > > > best regards,
> > > > > > > > > herman
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > > -----Original Message-----
> > > > > > > > > From: DIMITRIS TSOKAKIS
> > [mailto:TSOKAKIS@x...]
> > > > > > > > > Sent: Monday, October 25, 2004 1:57 AM
> > > > > > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > > > > > Subject: [amibroker] Re: DT's Ct
> prediction
> > > for
> > > > the
> > > > > Ti3
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > > --- In
amibroker@xxxxxxxxxxxxxxx, "Herman
> > van
> > > den
> > > > > Bergen"
> > > > > > > > > <psytek@xxxx> wrote:
> > > > > > > > > > DT, I am not sure i understand the
> > Ti3t...
> > > what
> > > > i am
> > > > > > trying
> > > > > > > to
> > > > > > > > find
> > > > > > > > > out is
> > > > > > > > > > what tomorrows closing price would be
> to
> > > cause
> > > > the
> > > > > > crossing
> > > > > > > of
> > > > > > > > two
> > > > > > > > > Ti3
> > > > > > > > > > functions.
> > > > > > > > >
> > > > > > > > > Herman,
> > > > > > > > > this specific question is already in
> > > > > > > > >
> > > http://finance.groups.yahoo.com/group/amibroker-
> > > > > > ts/files/A%
> > > > > > > 20Ti3%
> > > > > > > > > 20application/
> > > > > > > > > "Cross(Ti3a,Ti3b) predictions.txt"
> > > > > > > > > Dimitris
> > > > > > > > > For example:
> > > > > > > > > >
> > > > > > > > > > F1 = T3( Array1, 3, 0.8 );
> > > > > > > > > > F2 = T3( ref(Array2,-1), 3, 0.8 );
> > > > > > > > > >
> > > > > > > > > > Array1 and Array2 are two different
> > arrays
> > > and
> > > > > could be
> > > > > > any
> > > > > > > > type of
> > > > > > > > > > indicator array. For development you
> can
> > > plug in
> > > > > any of
> > > > > > the
> > > > > > > OHLC
> > > > > > > > > arrays, but
> > > > > > > > > > you cannot use the same price array
for
> > both
> > > > > function
> > > > > > > calles.
> > > > > > > > > > The Periods and Sensitivities are the
> > same
> > > for
> > > > both
> > > > > T3
> > > > > > > function
> > > > > > > > > calls.
> > > > > > > > > > F2 is based on yesterdays values, F1
is
> > > based on
> > > > > todays
> > > > > > > values.
> > > > > > > > > > I would like to calculate tomorrows
> value
> > > for
> > > > Array1
> > > > > > that
> > > > > > > would
> > > > > > > > > cause the
> > > > > > > > > > two functions to cross: cross(F1, F2).
> > > > > > > > > >
> > > > > > > > > > Do you think this is possible?
> > > > > > > > > >
> > > > > > > > > > thanks for you help DT!
> > > > > > > > > > herman
> > > > > > > > > > -----Original Message-----
> > > > > > > > > > From: DIMITRIS TSOKAKIS
> > > [mailto:TSOKAKIS@x...]
> > > > > > > > > > Sent: Saturday, October 23, 2004
5:34
> AM
> > > > > > > > > > To: amibroker@xxxxxxxxxxxxxxx
> > > > > > > > > > Subject: [amibroker] Re: DT's Ct
> > > prediction
> > > > for
> > > > > the
> > > > > > Ti3
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > > Herman,
> > > > > > > > > > Ti3t (the next bar Ti3) is a direct
> > > function
> > > > of
> > > > > the
> > > > > > next
> > > > > > > bar
> > > > > > > > > Close Ct.
> > > > > > > > > > Ti3t=
> > > > > > > > > > c1*(f*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+
> > > > > > > > > > (1-f)*e2)+(1-f)*e3)+(1-f)*e4)+(1-f)
> *e5)+
> > > (1-f)
> > > > *e6)+
> > > > > > > > > > c2*(f*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)
> *e2)
> > +
> > > (1-f)
> > > > *e3)
> > > > > +
> > > > > > > > > > (1-f)*e4)+(1-f)*e5)+
> > > > > > > > > > c3*(f*(f*(f*(f*Ct+(1-f)*e1)+(1-f)
*e2)+
> > (1-
> > > f)
> > > > *e3)+
> > > > > (1-f)
> > > > > > *e4)+
> > > > > > > > > > c4*(f*(f*(f*Ct+(1-f)*e1)+(1-f)*e2)+
(1-
> f)
> > > *e3);
> > > > > > > > > > If I understand your question, you
> want
> > to
> > > > solve
> > > > > Ct
> > > > > > for
> > > > > > > any
> > > > > > > > given
> > > > > > > > > > Ti3t.
> > > > > > > > > > Let me know and I will do it.
> > > > > > > > > > Dimitris
> > > > > > > > > > --- In
> > amibroker@xxxxxxxxxxxxxxx, "Herman
> > > van
> > > > den
> > > > > > Bergen"
> > > > > > > > > > <psytek@xxxx> wrote:
> > > > > > > > > > > Hello,
> > > > > > > > > > >
> > > > > > > > > > > 'been looking at DT's Ct formula
> (nice
> > > > work!) to
> > > > > > predict
> > > > > > > > where
> > > > > > > > > > tomorrow's
> > > > > > > > > > > Close will touch the Ti3 - see
code
> > > below.
> > > > Can
> > > > > > anybody
> > > > > > > see a
> > > > > > > > > way to
> > > > > > > > > > use this
> > > > > > > > > > > formula to predict the Close of
> > tomorrow
> > > > needed
> > > > > to
> > > > > > have
> > > > > > > the
> > > > > > > > Ti3
> > > > > > > > > > touch any
> > > > > > > > > > > arbitrary point? For example a
> point
> > on
> > > > another
> > > > > > > indicator.
> > > > > > > > > > >
> > > > > > > > > > > My math is not up to this, any
help
> > > would be
> > > > > > > appreciated!
> > > > > > > > > > >
> > > > > > > > > > > herman.
> > > > > > > > > > >
> > > > > > > > > > > p=3;s=0.84;f=2/(p+1);
> > > > > > > > > > > // Ti3
> > > > > > > > > > > e1=EMA(C,p);
> > > > > > > > > > > e2=EMA(e1,p);
> > > > > > > > > > > e3=EMA(e2,p);
> > > > > > > > > > > e4=EMA(e3,p);
> > > > > > > > > > > e5=EMA(e4,p);
> > > > > > > > > > > e6=EMA(e5,p);
> > > > > > > > > > > c1=-s*s*s;
> > > > > > > > > > > c2=3*s*s+3*s*s*s;
> > > > > > > > > > > c3=-6*s*s-3*s-3*s*s*s;
> > > > > > > > > > > c4=1+3*s+s*s*s+3*s*s;
> > > > > > > > > > > Ti3=c1*e6+c2*e5+c3*e4+c4*e3;
> > > > > > > > > > > //The value of tomorrow´s Close Ct
> > that
> > > > touches
> > > > > > > tomorrow´s
> > > > > > > > Ti3
> > > > > > > > > is
> > > > > > > > > > > Ct=
> > > > > > > > > > > (1-f)*
((c1*f^5+c2*f^4+c3*f^3+c4*f^2)
> > *e1+
> > > > > > > > > (c1*f^4+c2*f^3+c3*f^2+c4*f)
> > > > > > > > > > *e2+(c1*f
> > > > > > > > > > > ^3+c2*f^2+c3*f+c4*1)*e3+
> > > (c1*f^2+c2*f+c3*1)
> > > > *e4+
> > > > > > > (c1*f+c2*1)
> > > > > > > > > *e5+c1*e6)/
> > > > > > > > > > (1-(C1*f
> > > > > > > > > > >
> ^6+C2*f^5+C3*f^4+C4*f^3)) ;//relation
> > > III
> > > > > > > > > > > Plot(C,"Close",1,128);
> > > > > > > > > > > Plot(Ti3,"Ti3",4,1);
> > > > > > > > > > > Plot(Ct,"Ct",2,1);
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > > Check AmiBroker web page at:
> > > > > > > > > > http://www.amibroker.com/
> > > > > > > > > >
> > > > > > > > > > Check group FAQ at:
> > > > > > > > > >
> > > > > >
> > > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > > Yahoo! Groups Sponsor
> > > > > > > > > > ADVERTISEMENT
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > > --------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > ----
> > > > > > ----
> > > > > > > ----
> > > > > > > > ----
> > > > > > > > > --------
> > > > > > > > > > --
> > > > > > > > > > Yahoo! Groups Links
> > > > > > > > > >
> > > > > > > > > > a.. To visit your group on the
web,
> > go
> > > to:
> > > > > > > > > >
> > http://groups.yahoo.com/group/amibroker/
> > > > > > > > > >
> > > > > > > > > > b.. To unsubscribe from this
group,
> > > send an
> > > > > email
> > > > > > to:
> > > > > > > > > > amibroker-
> unsubscribe@xxxxxxxxxxxxxxx
> > > > > > > > > >
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> > > subject to
> > > > the
> > > > > > Yahoo!
> > > > > > > > Terms of
> > > > > > > > > Service.
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > >
> > > > > > > > > > [Non-text portions of this message
have
> > been
> > > > > removed]
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > >
> > > > > > > > > Check AmiBroker web page at:
> > > > > > > > > http://www.amibroker.com/
> > > > > > > > >
> > > > > > > > > Check group FAQ at:
> > > > > > > > >
> > > > >
> http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > > > > > >
> > > > > > > > >
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> > > > > > > > > ------------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > ----
> > > > > > ----
> > > > > > > ----
> > > > > > > > --------
> > > > > > > > > --
> > > > > > > > > Yahoo! Groups Links
> > > > > > > > >
> > > > > > > > > a.. To visit your group on the web, go
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> > > > > > > > >
> > > > > > > > >
> > > > > > > > > [Non-text portions of this message have
been
> > > > removed]
> > > > > > > >
> > > > > > > >
> > > > > > > >
> > > > > > > >
> > > > > > > >
> > > > > > > > Check AmiBroker web page at:
> > > > > > > > http://www.amibroker.com/
> > > > > > > >
> > > > > > > > Check group FAQ at:
> > > > > > > >
> > > > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > > > > >
> > > > > > > >
> > > > > > > > Yahoo! Groups Sponsor
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> > > > > > > > ----------------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > ----
> > > > > > ----
> > > > > > > --------
> > > > > > > > --
> > > > > > > > Yahoo! Groups Links
> > > > > > > >
> > > > > > > > a.. To visit your group on the web, go to:
> > > > > > > > http://groups.yahoo.com/group/amibroker/
> > > > > > > >
> > > > > > > > b.. To unsubscribe from this group, send
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> > > > to:
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> > the
> > > > Yahoo!
> > > > > > Terms of
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> > > > > > > >
> > > > > > > >
> > > > > > > > [Non-text portions of this message have been
> > > removed]
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > Check AmiBroker web page at:
> > > > > > > http://www.amibroker.com/
> > > > > > >
> > > > > > > Check group FAQ at:
> > > > > > >
> > > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > > > >
> > > > > > >
> > > > > > > Yahoo! Groups Sponsor
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> > > > > > >
> > > > > > >
> > > > > > > --------------------------------------------------
--
> --
> > --
> > > ----
> > > > ----
> > > > > ----
> > > > > > --------
> > > > > > > --
> > > > > > > Yahoo! Groups Links
> > > > > > >
> > > > > > > a.. To visit your group on the web, go to:
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> > > > > > > b.. To unsubscribe from this group, send an
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> > > > > > > c.. Your use of Yahoo! Groups is subject to
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> > > Yahoo!
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> > > > > > >
> > > > > > >
> > > > > > >
> > > > > > > [Non-text portions of this message have been
> removed]
> > > > > >
> > > > > >
> > > > > >
> > > > > >
> > > > > >
> > > > > > Check AmiBroker web page at:
> > > > > > http://www.amibroker.com/
> > > > > >
> > > > > > Check group FAQ at:
> > > > > >
> > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > > >
> > > > > >
> > > > > > Yahoo! Groups Sponsor
> > > > > > ADVERTISEMENT
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> > > > > >
> > > > > > ------------------------------------------------------
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> > > ----
> > > > ----
> > > > > --------
> > > > > > --
> > > > > > Yahoo! Groups Links
> > > > > >
> > > > > > a.. To visit your group on the web, go to:
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> > > > > >
> > > > > > b.. To unsubscribe from this group, send an email
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> > > > > >
> > > > > > c.. Your use of Yahoo! Groups is subject to the
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> > > > Terms of
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> > > > > >
> > > > > > [Non-text portions of this message have been removed]
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> > > > >
> > > > >
> > > > >
> > > > > Check AmiBroker web page at:
> > > > > http://www.amibroker.com/
> > > > >
> > > > > Check group FAQ at:
> > > > >
http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > > >
> > > > >
> > > > > Yahoo! Groups Sponsor
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> > > > > ----------------------------------------------------------
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> > > ----
> > > > --------
> > > > > --
> > > > > Yahoo! Groups Links
> > > > >
> > > > > a.. To visit your group on the web, go to:
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> > > > > b.. To unsubscribe from this group, send an email to:
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> > > > > c.. Your use of Yahoo! Groups is subject to the Yahoo!
> > > Terms of
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> > > > >
> > > > >
> > > > >
> > > > > [Non-text portions of this message have been removed]
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> > > >
> > > >
> > > >
> > > >
> > > > Check AmiBroker web page at:
> > > > http://www.amibroker.com/
> > > >
> > > > Check group FAQ at:
> > > > http://groups.yahoo.com/group/amibroker/files/groupfaq.html
> > > >
> > > >
> > > > Yahoo! Groups Sponsor
> > > > ADVERTISEMENT
> > > >
> > > >
> > > >
> > > >
> > > >
> > > > --------------------------------------------------------------
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> > --
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> > > > --
> > > > Yahoo! Groups Links
> > > >
> > > > a.. To visit your group on the web, go to:
> > > > http://groups.yahoo.com/group/amibroker/
> > > >
> > > > b.. To unsubscribe from this group, send an email to:
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> > > >
> > > > c.. Your use of Yahoo! Groups is subject to the Yahoo!
> Terms
> > of
> > > Service.
> > > >
> > > >
> > > >
> > > > [Non-text portions of this message have been removed]
>
>
>
>
>
> Check AmiBroker web page at:
> http://www.amibroker.com/
>
> Check group FAQ at:
> http://groups.yahoo.com/group/amibroker/files/groupfaq.html
>
>
> Yahoo! Groups Sponsor
> ADVERTISEMENT
>
>
>
>
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>
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>
> To visit your group on the web, go to:
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> Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service.
Check AmiBroker web page at:
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Check group FAQ at:
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Yahoo! Groups Links
a.. To visit your group on the web, go to:
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b.. To unsubscribe from this group, send an email to:
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c.. Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service.
[Non-text portions of this message have been removed]
------------------------ Yahoo! Groups Sponsor --------------------~-->
$9.95 domain names from Yahoo!. Register anything.
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--------------------------------------------------------------------~->
Check AmiBroker web page at:
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Check group FAQ at: http://groups.yahoo.com/group/amibroker/files/groupfaq.html
Yahoo! Groups Links
<*> To visit your group on the web, go to:
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