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Re: [amibroker] Re: Sigma Bands



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how about a simple loop, I 
will just type one here so no guarantee it is completely 
correct
 
Cond = 
WhatYourCondIs;//make this binary ie 0 or 1
<FONT 
face=Arial>Result=0;
for ( 
k=25;k>=10;k--)
{ <SPAN 
class=564423400-20022004>if ( sum(Cond,k)>0) {Result = k;} 
<FONT 
face=Arial>}
FinalResult = 
Result>0;
 
Cheers,Graham<A 
href="">http://e-wire.net.au/~eb_kavan/ 


  
  <FONT 
  face=Tahoma size=2>-----Original Message-----From: mrdavis9 
  [mailto:mrdavis9@xxxxxxxxxx] Sent: Friday, 20 February 2004 7:48 
  AMTo: amibroker@xxxxxxxxxxxxxxxSubject: Re: [amibroker] 
  Re: IsNotThere(Array or Ref(Array,-1) or Ref(Array,-1) or
  I am going to code an exploration that 
   looks back over the last 25 daily bars to see if an Array condition has 
  been met on ALL of the last 25 bars.   If it fails to find that 
  ALL of the last 25 bars are true, it will then look for 24 true bars, 
  then 23 true bars, and so on till it finally quits looking at about 10 bars 
  back.  I can code this  with lots of repititons of coding, 
  but I would like to find a more elegant way to code it.  
   
  I was unable to divise a way to do this with Sum() or 
  Cum().  Is there any other simple way to code this? 
   
  If loops is the way to go, then I would sure appreciate 
  seeing this coded with loops.  I learn best by seeing a working example 
  of something that I am attempting to do.  TIA  Ron 
  D 
   
   
  <BLOCKQUOTE 
  >
    ----- Original Message ----- 
    <DIV 
    >From: 
    johsun 
    
    To: <A title=amibroker@xxxxxxxxxxxxxxx 
    href="">amibroker@xxxxxxxxxxxxxxx 
    Sent: Wednesday, February 18, 2004 
    11:42 AM
    Subject: [amibroker] Re: 
    IsNotThere(Array or Ref(Array,-1) or Ref(Array,-1) or
    cond=Your conditionx=Sum(cond,4)>=1;this will 
    return True if cond has occurred in the last four days including today. 
    Is that what you wanted?JS--- In <A 
    href="">amibroker@xxxxxxxxxxxxxxx, 
    "mrdavis9" <mrdavis9@x...> 
    wrote:> Below is coding that allows the  Seq10e2up2e10 OR 
    SeqR14toR14e15 conditions to have occurred upto three days before the 
    RSIEMA2cross occurs.  Is there a lot more elegant and simple way to 
    do this?> > An  IsNotThere(Array) would do what I 
    want.  Is there one that I missed that can be made to work.  I 
    still have not been able to grasp doing loops.  If looping is a 
    good way to do this, I would sure appreciate seeing the below IIF coding 
    made into a looping function.  Then, by knowing what it is designed 
    to do, I should be able to finally understand how looping works.  
    Ron D> > Day3a=IIf(Ref(Seq10e2up2e10 OR 
    SeqR14toR14e15,-3),1,0);> > Day3=IIf(Ref(Seq10e2up2e10 OR 
    SeqR14toR14e15,-3),1,0);> > Day2a=IIf(Ref(Seq10e2up2e10 OR 
    SeqR14toR14e15,-1),1,day3a);> > Day2=IIf(Ref(Seq10e2up2e10 OR 
    SeqR14toR14e15,-2),Day3,0);> > Day1a=IIf(Ref(Seq10e2up2e10 OR 
    SeqR14toR14e15,-1),Day2,Day2a);> > Day1=IIf(Ref(Seq10e2up2e10 
    OR SeqR14toR14e15,-1),Day2,0);> > Day0a=IIf(Seq10e2up2e10 OR 
    SeqR14toR14e15,Day1,Day1a);> > 
    Day0=IIf(RSIEMA2cross,Day0a,0);Send BUG REPORTS to <A 
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