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The horizontality does not need special care.
Any y=3; line will be horizontal [equal to 3 for any bar]
A y=lastvalue(highest(C)); will be also horizontal, equal to the
highest Close price.
A y=highest(C); will not be horizontal as [probable]new highs are
added to the Close array. If your data are from 1996 till now, the
highest(C) was not ALWAYS the lastvalue(highest(C)) we know today.
Dimitris Tsokakis
--- In amibroker@xxxxxxxxxxxxxxx, "gillesdeprez" <gillesdeprez@xxxx>
wrote:
> Yes,a 100 bars would be perfect, can we use it as max in "param"? I
> would use 60 as default, what do you think?
> Btw,2 points can define parallel lines (and an infinity as well),
how
> do you express the horizontality?
>
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
<TSOKAKIS@xxxx>
> wrote:
> > I need two points to define an horizontal channel, one high and
one
> > low.
> > What would you prefer for the definition ?
> > It could be, for example the highest and the lowest of the last
100
> > bars.
> > Describe your requirement with some more details and we shall
give
> it
> > a try.
> > Mitsos
> > --- In amibroker@xxxxxxxxxxxxxxx, "gillesdeprez"
> <gillesdeprez@xxxx>
> > wrote:
> > > Good afternoon, Dimitri!
> > > Back in Belgium,and believe me the weather here is awful!!
> > > Say, based on the formulas you've recently presented here,
would
> it
> > > be possible to set up an horizontal channel breakout
detection ,
> > with
> > > the looback and amplitude of the channel adjustable via the
param
> > > function? I didn't found anything like that in the library...
> > > Have a nice day,
> > > Friendly,
> > > Gilles
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