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Thanks, already came up with something similar (via index
manipulation) that seems to work.
a
--- In amibroker@xxxxxxxxxxxxxxx, "Bob Jagow" <bjagow@xxxx> wrote:
> No, but you can apparently fake it via index manipulation--see the
pasted reply from Tomasz below. -Bob.
> ---
> Hello,
>
> 1. 'break' statement is not implemented (and I don't give any
> warranty it will be, although I am thinking of it)
>
> 2. No, array is not filled with zeros. Internally it is just
malloc()-ed
>
> Best regards,
> Tomasz Janeczko
> amibroker.com
> ----- Original Message -----
> From: "Michael Orlyk" <bmwrider@xxxx>
> To: <amibroker@xxxxxxxxxxxxxxx>
> Sent: Thursday, April 17, 2003 2:59 AM
> Subject: [amibroker] Breaking out of a for(; ; ) loop
>
>
> > Please confirm that the break keyword has no functionality in the
new
> > AFL for(;;) loops. As an example the following code snippet did
not
> > produce a break out of the loop when executed yet AFL didn't
complain
> > about the presence of the key word break:
> >
> > for(i=1;i<BarCount; i++) {
> > if (H[i] > H[i-1]){
> > y[i] = H[i];
> > if (y[i] >= 22.00)
> > break; // did not cause an exit out of the loop
> > }
> > else
> > y[i] = L[i];
> > }
> >
> > As a work around I coded the loop as follows to simulate a break:
> >
> > for(i=1, j=BarCount; i<j; i++) {
> > if (H[i] > H[i-1]){
> > y[i] = H[i];
> > if (y[i] >= 22.00)
> > j=i;
> > }
> > else
> > y[i] = L[i];
> > }
> >
> > I also have a question: when an array variable is declared, can
I
> > assume all the array elements are initialized to zero?
> >
> > Thanks ...
> >
> > Mike O.
> >
> -------
>
> -----Original Message-----
> From: aequalsz [mailto:aequalsz@x...]
> Sent: Tuesday, June 03, 2003 9:12 AM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] for loop
>
>
> I'm translating a Metastock Developers Kit C++ code to Amibroker AFL
> but have hit a minor snag. Is there any way to prematurely BREAK
out
> of a for loop?
>
> a
>
>
>
> Send BUG REPORTS to bugs@xxxx
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