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No, but you can apparently fake it via index manipulation--see the pasted reply from Tomasz below. -Bob.
---
Hello,
1. 'break' statement is not implemented (and I don't give any
warranty it will be, although I am thinking of it)
2. No, array is not filled with zeros. Internally it is just malloc()-ed
Best regards,
Tomasz Janeczko
amibroker.com
----- Original Message -----
From: "Michael Orlyk" <bmwrider@xxxxxxxxxxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Thursday, April 17, 2003 2:59 AM
Subject: [amibroker] Breaking out of a for(; ; ) loop
> Please confirm that the break keyword has no functionality in the new
> AFL for(;;) loops. As an example the following code snippet did not
> produce a break out of the loop when executed yet AFL didn't complain
> about the presence of the key word break:
>
> for(i=1;i<BarCount; i++) {
> if (H[i] > H[i-1]){
> y[i] = H[i];
> if (y[i] >= 22.00)
> break; // did not cause an exit out of the loop
> }
> else
> y[i] = L[i];
> }
>
> As a work around I coded the loop as follows to simulate a break:
>
> for(i=1, j=BarCount; i<j; i++) {
> if (H[i] > H[i-1]){
> y[i] = H[i];
> if (y[i] >= 22.00)
> j=i;
> }
> else
> y[i] = L[i];
> }
>
> I also have a question: when an array variable is declared, can I
> assume all the array elements are initialized to zero?
>
> Thanks ...
>
> Mike O.
>
-------
-----Original Message-----
From: aequalsz [mailto:aequalsz@xxxxxxxxx]
Sent: Tuesday, June 03, 2003 9:12 AM
To: amibroker@xxxxxxxxxxxxxxx
Subject: [amibroker] for loop
I'm translating a Metastock Developers Kit C++ code to Amibroker AFL
but have hit a minor snag. Is there any way to prematurely BREAK out
of a for loop?
a
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