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Fred,
I just provided the proof, if someone needs it.
DT
--- In amibroker@xxxxxxxxxxxxxxx, "Fred" <fctonetti@xxxx> wrote:
> i.e they are the same or is that what you said that I said ?
>
> --- In amibroker@xxxxxxxxxxxxxxx, "DIMITRIS TSOKAKIS"
<TSOKAKIS@xxxx>
> wrote:
> > Fred,
> >
> > T = 10; // Time Period
> > M = (H+L)/2;// your array here
> > EMA1 = EMA(M,T);
> > EMA2 = EMA(EMA1,T);
> > Diff = EMA1 - EMA2;
> > ZeroLagEMA = EMA1 + Diff;
> > Graph0 = ZeroLagEMA;
> >
> > Following above defined ZeroLagEMA we have
> > ZeroLagEMA = EMA1 + Diff=EMA1+(EMA1-EMA2)=2*EMA1-EMA2=2*EMA(M,T)-
EMA
> > (EMA(M,T),T)
> > The last part is DEMA(M,T) [see also
> > http://www.amibroker.com/guide/afl/afl_view.php?id=42]
> > DT
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "Fred" <fctonetti@xxxx> wrote:
> > > Use the built in DEMA ... you'll get the same thing as the
> > intention
> > > of what you posted even though it's missing the definition of
> EMA2.
> > >
> > > --- In amibroker@xxxxxxxxxxxxxxx, "traderix2003" <d.adam@xxxx>
> > wrote:
> > > > Has somebody the formula for a " zero lag EMA"?
> > > > A friend of mine gave me the Metastock formula. Perhaps some
> one
> > > > could translate it:
> > > >
> > > > Zero Lag EMA
> > > > Period:=Input("What Period",1,250,10);
> > > > EMA1=Mov(P,Period,E);
> > > > Difference:=EMA1 - EMA2;
> > > > ZeroLagEMA:=EMA1 + Difference;
> > > > ZeroLagEMA
> > > >
> > > > Thxs for your help.
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