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Dimitris,
Each task can be performed in numerous of ways.
In that case there are at least a handful of methods.
This time I presented 2 methods (AMA and looping),
but ValueWhen works good as well.
Excuse me but I can not give 10 examples on doing the same
thing in various ways because I am quite busy doing
more important things (like developing next version)
Best regards,
Tomasz Janeczko
amibroker.com
----- Original Message -----
From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxxxxxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Thursday, May 08, 2003 3:17 PM
Subject: [amibroker] Re: How to solve in AFL.....
> Tomasz,
> then we speak for a ValueWhen(Cond,a*b), right ?
> DT
> PS: I think ValueWhen(Cond,Array) is equivalent to AMA(Array,Cond),
> we have discussed it in the past [I was suggesting AMA and you
> suggested Valuewhen this time...], but I do not know if above
> equivalence is ALWAYS true. Do you see any exception perhaps?
> --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" <amibroker@xxxx>
> wrote:
> > Dimitris,
> >
> > There is "third possibility" - {EMPTY} or Null value
> > but this possibility is handled automatically by AB
> > so indeed single IIF is perfectly enough.
> >
> > Best regards,
> > Tomasz Janeczko
> > amibroker.com
> > ----- Original Message -----
> > From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Thursday, May 08, 2003 2:45 PM
> > Subject: [amibroker] Re: How to solve in AFL.....
> >
> >
> > > Tomasz,
> > > Let us look at the question first :
> > > Your code is [I suppose] for the question
> > > x = IIF(Condition is TRUE, a * b, Ref(x,-1));
> > > Keith question was
> > > x = IIF(Condition is TRUE, a * b,
> > > IIF(Condition is FALSE, Ref(x,-1),NULL));
> > > I think it does not make sense because Condition is TRUE OR FALSE
> > > without 3rd possibility
> > > DT
> > >
> > >
> > > --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko"
> <amibroker@xxxx>
> > > wrote:
> > > > Hello,
> > > >
> > > > Using AMA/AMA2:
> > > >
> > > > x = AMA( a * b, Condition == True );
> > > >
> > > > Using loops:
> > > >
> > > > for( i = 1; i < BarCount; i++ )
> > > > {
> > > > if( Condition[ i ] )
> > > > {
> > > > x[ i ] = a * b;
> > > > }
> > > > else
> > > > {
> > > > x[ i ] = x[ i - 1 ];
> > > > }
> > > > }
> > > >
> > > >
> > > > Best regards,
> > > > Tomasz Janeczko
> > > > amibroker.com
> > > > ----- Original Message -----
> > > > From: "Keith Bennett" <kbennett@xxxx>
> > > > To: <amibroker@xxxxxxxxxxxxxxx>
> > > > Sent: Thursday, May 08, 2003 12:33 PM
> > > > Subject: [amibroker] How to solve in AFL.....
> > > >
> > > >
> > > > >
> > > > > Hi,
> > > > >
> > > > > The following situation frequently occurs, but it doesn't
> seem
> > > > > possible to solve directly due to the self reference.
> > > > >
> > > > > How do you tackle this in AFL:
> > > > >
> > > > > x = IIF(Condition is TRUE, a * b,
> > > > > IIF(Condition is FALSE, Ref(x,-1),NULL));
> > > > >
> > > > > Thanks
> > > > > Keith
> > > > >
> > > > >
> > > > >
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