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Tomasz,
then we speak for a ValueWhen(Cond,a*b), right ?
DT
PS: I think ValueWhen(Cond,Array) is equivalent to AMA(Array,Cond),
we have discussed it in the past [I was suggesting AMA and you
suggested Valuewhen this time...], but I do not know if above
equivalence is ALWAYS true. Do you see any exception perhaps?
--- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" <amibroker@xxxx>
wrote:
> Dimitris,
>
> There is "third possibility" - {EMPTY} or Null value
> but this possibility is handled automatically by AB
> so indeed single IIF is perfectly enough.
>
> Best regards,
> Tomasz Janeczko
> amibroker.com
> ----- Original Message -----
> From: "DIMITRIS TSOKAKIS" <TSOKAKIS@xxxx>
> To: <amibroker@xxxxxxxxxxxxxxx>
> Sent: Thursday, May 08, 2003 2:45 PM
> Subject: [amibroker] Re: How to solve in AFL.....
>
>
> > Tomasz,
> > Let us look at the question first :
> > Your code is [I suppose] for the question
> > x = IIF(Condition is TRUE, a * b, Ref(x,-1));
> > Keith question was
> > x = IIF(Condition is TRUE, a * b,
> > IIF(Condition is FALSE, Ref(x,-1),NULL));
> > I think it does not make sense because Condition is TRUE OR FALSE
> > without 3rd possibility
> > DT
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko"
<amibroker@xxxx>
> > wrote:
> > > Hello,
> > >
> > > Using AMA/AMA2:
> > >
> > > x = AMA( a * b, Condition == True );
> > >
> > > Using loops:
> > >
> > > for( i = 1; i < BarCount; i++ )
> > > {
> > > if( Condition[ i ] )
> > > {
> > > x[ i ] = a * b;
> > > }
> > > else
> > > {
> > > x[ i ] = x[ i - 1 ];
> > > }
> > > }
> > >
> > >
> > > Best regards,
> > > Tomasz Janeczko
> > > amibroker.com
> > > ----- Original Message -----
> > > From: "Keith Bennett" <kbennett@xxxx>
> > > To: <amibroker@xxxxxxxxxxxxxxx>
> > > Sent: Thursday, May 08, 2003 12:33 PM
> > > Subject: [amibroker] How to solve in AFL.....
> > >
> > >
> > > >
> > > > Hi,
> > > >
> > > > The following situation frequently occurs, but it doesn't
seem
> > > > possible to solve directly due to the self reference.
> > > >
> > > > How do you tackle this in AFL:
> > > >
> > > > x = IIF(Condition is TRUE, a * b,
> > > > IIF(Condition is FALSE, Ref(x,-1),NULL));
> > > >
> > > > Thanks
> > > > Keith
> > > >
> > > >
> > > >
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