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2nd try, first didnt post
Yahoo is buggy today,
I had replied to UM about the mistake i made using a single minus in
the decrement examples.
After checking my manual i realised a double minus is shown as 1
long minus.
Your posts were in the middle of these.
Thanks for the imfo as i only have started learning from a very
basic manual, since the new loops where added in ami.
Peter.
--- In amibroker@xxxxxxxxxxxxxxx, "bluesinvestor" <investor@xxxx>
wrote:
> I am not sure what you mean?? My post was in reference to the
shorthand
> you provided for self-assigned addition and subtraction
(multiplication,
> division and modulus operations also). While they do exist in C++
and
> Javascript, they do not function properly in Amibroker yet.
>
> Regards,
> Peter
>
> -----Original Message-----
> From: amiabilityy [mailto:amiabilityy@x...]
> Sent: Wednesday, April 30, 2003 2:30 PM
> To: amibroker@xxxxxxxxxxxxxxx
> Subject: [amibroker] Re: Motr loop questions
>
>
> My manual is decieving,
>
> The double minus is actually shown as 1 long minus, when compared
> to a sample formula using a single minus.
>
>
>
> Peter.
>
> --- In amibroker@xxxxxxxxxxxxxxx, "bluesinvestor" <investor@xxxx>
> wrote:
> > Peter (this could get confusing),
> >
> > > There is another short hand writing:
> > >
> > > x += y means x = x + y
> > > x -= y means x = x - y
> >
> > See my prior post ... Amibroker does not use this short hand yet.
> >
> > Regards,
> > Peter
> >
> > -----Original Message-----
> > From: uenal.mutlu@xxxx [mailto:uenal.mutlu@x...]
> > Sent: Wednesday, April 30, 2003 12:07 PM
> > To: amibroker@xxxxxxxxxxxxxxx
> > Subject: Re: [amibroker] Re: Motr loop questions
> >
> > Hi Peter,
> > the latter two forms in your posting should be IMHO not correct.
> > Otherwise negation of a variable, fe. -myvar) would
> > not function. Please see TJ's postings on that.
> >
> > As Tomasz wrote, the increment and decrement operators
> > are alternative shorthand writings. Here is a summary:
> >
> > x = --i means i = i - 1; x = i
> > x = ++i means i = i + 1; x = i
> > x = i-- means x = i; i = i - 1
> > x = i++ means x = i; i = i + 1
> >
> > There is another short hand writing:
> >
> > x += y means x = x + y
> > x -= y means x = x - y
> >
> > It is not a must to use these shorthand writings; one
> > should use the variant which one likes most.
> >
> > UM
> >
> >
> > ----- Original Message -----
> > From: "amiabilityy" <amiabilityy@xxxx>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Wednesday, April 30, 2003 5:27 PM
> > Subject: [amibroker] Re: Motr loop questions
> >
> >
> > The ++ operator is used to express incrementing directly rather
than
> > the more long winded and equally correct i += 1 or i = i + 1
> > There are two forms of the increrment
> > (and 2 corresponding forms of the decrement)
> >
> > i++ post-increment.
> > ++i pre- increment.
> > i- post-decrement.
> > -i pre-decrement.
> >
> > These are expresions that return a value
> > The post increment form returns the value of i after it has been
> > incremented, while the pre increment form returns the value
before i
> > was incremented.
> >
> > Note: i am not sure if ami can use the decrement forms.
> >
> >
> > Peter.
> >
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "IVA GmbH" <funnybiz@xxxx>
wrote:
> > > Hello,
> > >
> > > I´d appreciate if someone ould clarify the following "loop
> > questions":
> > >
> > > 1./ Where in the AFL code can those loops if/else and why/for be
> > embedded? Just anywhere, where they´re needed?
> > >
> > > 2./ Can we have nested loops?
> > >
> > > 3./ In case of severeal loops in my code, can I use any letter
> > instead of the "i" for the iteration part so that AFL doesn´t get
> > mixed up?
> > >
> > > 4./ What is the difference between "i++" and "++i". I saw it in
> one
> > of -I believe- TJ´s posts.
> > >
> > > Many thanks
> > >
> > > Markus
> >
> >
> >
> >
> > Send BUG REPORTS to bugs@xxxx
> > Send SUGGESTIONS to suggest@xxxx
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>
>
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