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Tomasz AB is the
best. This example of Jason's does run and produce results so AB does
evaluate the if expression but the results are strange and do not agree with the
IIF function results. see attached gif. Would you explain what is
happening? I know you believe it is incorrect expression but there is no
error generated by AB.
thanks
tom
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"Tomasz Janeczko"
<<A
href=""><FONT
face="Courier New" size=3>amibroker@xxxx<FONT face="Courier New"
size=3>> wrote:> Hello,> > About new if-else>
if-else statement changes flow of execution (opposite to IIF function that
evaluates all arguments).> and you can not really write> >
if (H >Ref(H,-1))> > because it has no meaning. It would
translate to > "If high array is higher than high array shifted one bar"
(see tutorial below)> flow control statement has to get SINGLE
boolean value to make decision which> execution path should be taken.
> If you write H (or High) it means ARRAY (entire array) > if you
write H[ i ] - it means i-th element of the array. The subscript operator [
] > allows you to access individual array elements.> >
Instead you should write:> > for( i = 1; i < BarCount; i++
)> {> if ( H[ i ] > H[ i - 1 ] )> x[ i ] = H[ i
];> else> x[ i ] = L[ i ];> }> > >
this will translate to correct one> "for EVERY BAR 'i' assign i-th
element of high array to the i-th element of x array if> i-th element
of high array is higher than the previous element, otherwise assign i-th
of> low array to the i-th element of x array"> > As you can
see in many cases old-style AFL provides much more compact> form. I
always tried to explain this advantage of AFL but only a few realised
that.> New control statements should be used where it is better to use
them.> As I tried to explain during last years in 80% of cases
'old-style' AFL provides> the shortest formula. Only remaining 20% of
cases needed script.> Those 'script-only' cases now can be coded in
native AFL thanks to new for/while/if-else> statements. And this is
correct usage of them - TO REPLACE SCRIPT PARTS.>
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