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Re: [amibroker] Bang For Bucks Formula



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Hi Tomasz,

Would you please provide the Metastock "W" weighting averaging,
AFL procedure?

  Mov( array, period, W)
translates to AFL's
  ?MA( array,  period )

I have no idea unless it's AMA, but that's a pure guess

Regards, 

Hal

At 01:42 PM 6/25/01 +0200, you wrote:
Hi Geoff,
 
Please remember that
Metastock's simple moving average
 Mov( array, period, S ) 
translates to AFL's:
  MA( array, period )
 
While exponential moving average:
  Mov( array, period, E )
translates to AFL's
  EMA( array, period )
 
So the result of the translation is:
Per1 = 200; 
Range =ATR(1); 
A =((10000/C)* ( MA( Range, Per1 ))/100 ); 
 

Best regards,
Tomasz Janeczko
------------------------------------------------
AmiBroker - the comprehensive share manager
http://www.amibroker.com

----- Original Message ----- 
From:
gmulhall@xxxx 
To:
amibroker@xxxxxxxxxxxxxxx 
Sent: Monday, June 25, 2001 11:31 AM 
Subject: [amibroker] Bang For Bucks Formula 


Steve (Wiser)


Here's an updated formula from Chris Tate. 


Can you assist with another translation from Metastock please ?


Regards,


Geoff


------------------------------------------------------------------


From: Christopher Tate 
To: Geoff Mulhall 
Sent: Sunday, June 24, 2001 9:56 AM 
Subject: Re: New Bang for Buck Formula 






Per1:= 200; 
Range:=ATR(1); 
A:=((10000/C)* (Mov(Range,Per1,S))/100); 
A; 


















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