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Re: [amibroker] Bang For Bucks Formula



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Hi Geoff,
 
Please remember that
Metastock's simple moving average
 Mov( array, period, S ) 
translates to AFL's:
  MA( array, period 
)
 
While exponential moving average:
  Mov( array, period, E )
translates to AFL's
  EMA( array, period )
 
So the result of the translation is:
Per1 = 200; Range =ATR(1); A =((10000/C)* 
( MA( Range, Per1 ))/100 ); 
 
Best regards,Tomasz 
Janeczko------------------------------------------------AmiBroker -the 
comprehensive share manager<A 
href="">http://www.amibroker.com
<BLOCKQUOTE 
>
----- Original Message ----- 
<DIV 
>From: 
<A title=gmulhall@xxxx 
href="">gmulhall@xxxx 
To: <A title=amibroker@xxxxxxxxxxxxx 
href="">amibroker@xxxxxxxxxxxxxxx 
Sent: Monday, June 25, 2001 11:31 
AM
Subject: [amibroker] Bang For Bucks 
Formula 
<FONT 
size=2>Steve (Wiser)Here's an 
updated formula from Chris Tate. Can you assist with another 
translation from Metastock please 
?Regards,Geoff------------------------------------------------------------------From: 
Christopher Tate To: Geoff Mulhall Sent: Sunday, June 24, 2001 9:56 AM 
Subject: Re: New Bang for Buck Formula Per1:= 200; 
Range:=ATR(1); A:=((10000/C)* (Mov(Range,Per1,S))/100); A; 
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