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Hi,
Here are some alternative of Pivots points calculations including the
camarilla one you asked for.
I know nothing about Gann square of nine pivots calculations.
Let me know if you find something on it so I can know about it.
Regards
Philippe
Alternate Pivot Point calculations
The Alternate Pivot Points page has the following 3 types of pivot points
calculations on it.
Classic Formula
R4 = R3 + RANGE (same as: PP + RANGE * 3)
R3 = R2 + RANGE (same as: PP + RANGE * 2)
R2 = PP + RANGE
R1 = (2 * PP) - LOW
PP = (HIGH + LOW + CLOSE) / 3
S1 = (2 * PP) - HIGH
S2 = PP - RANGE
S3 = S2 - RANGE (same as: PP - RANGE * 2)
S4 = S3 - RANGE (same as: PP - RANGE * 3)
Woodie Pivot Points
R4 = R3 + RANGE
R3 = H + 2 * (PP - L) (same as: R1 + RANGE)
R2 = PP + RANGE
R1 = (2 * PP) - LOW
PP = (HIGH + LOW + CLOSE) / 3
S1 = (2 * PP) - HIGH
S2 = PP - RANGE
S3 = L - 2 * (H - PP) (same as: S1 - RANGE)
S4 = S3 - RANGE
Camarilla Pivot Points
R4 = C + RANGE * 1.1/2
R3 = C + RANGE * 1.1/4
R2 = C + RANGE * 1.1/6
R1 = C + RANGE * 1.1/12
PP = (HIGH + LOW + CLOSE) / 3
S1 = C - RANGE * 1.1/12
S2 = C - RANGE * 1.1/6
S3 = C - RANGE * 1.1/4
S4 = C - RANGE * 1.1/2
Tom DeMark "Pivot Points"
Condition C < O C > O C = 0
X (H + (L * 2) + C) ((H * 2) + L + C) (H + L + (C * 2))
R1 = X / 2 - L
PP = X / 4 (this is not an official DeMark number but merely a reference
point based on the calculation of X)
S1 = X / 2 - H
Theses are from the following link :
http://www.deltat1.com/DailyNotes/notes5.htm#demark
> -----Message d'origine-----
> De : mbaum@xxxxxxxxxxx [mailto:mbaum@xxxxxxxxxxx]
> Envoyé : mercredi 13 septembre 2006 23:13
> À : omega-list@xxxxxxxxxx
> Objet : Gann Square of 9 / Camarilla plot points
>
> I use Tradestation 8.1(build 3247). I am looking for 2 things
>
>
> 1. the equations to use the CAMARILLO PIVOT TRADER POINTS
>
> 2. the equations to use the GANN(square of 9) Pivot Trader Points.
>
> Would anyone know where I could obtain these. I have the easy language
> indicators that I can insert the formulas into.
>
> Your help would be appreciated.
>
> Thanks
>
> Mark S. Baum
> mbaum@xxxxxxxxxxx
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