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On Thu, 19 Dec 2002 22:11 +0000 (GMT Standard Time)
ianwaugh@xxxxxxxxx (Ian Waugh) wrote:
> I got that far (:-) but it doesn't have to be the very next bar.
It's not clear to me what you want to do. You could plot paint bars and show me stuff starting with the code below.
Or are you trying to write a system that would buy / sell those swing breakouts?
IF C < SWINGHIGH(1,C,2,33) or C < SWINGHIGH(1,C[1],2,33)
.....
> Theoretically, it could take forever but that hasn't happened yet...
>
> Cheers,
> Ian
>
> > {we need a bar that *closes* lower than either of
> > > > the first two bars.}
> >
> >
> > If C < C[1] or C < C[2] then begin
> > IF H < SWINGHIGH(1,H,2,33)....
> >
> > On Thu, 19 Dec 2002 16:37 +0000 (GMT Standard Time)
> > ianwaugh@xxxxxxxxx (Ian Waugh) wrote:
> > > Gosh, is this as difficult as my limited EL abilities think it
> > > is...?
> > >
> > > Cheers,
> > > Ian
> > >
> > > > Hi All,
> > > > I was wondering if someone a bit more versed in El than me
> > > > could help with this.
> > > >
> > > > I'm trying to define a swing point, let's say a high, but it's
> > > > not like a "standard" high that has a lower high on either side,
> > > > I'd like to define a Swing high like this:
> > > >
> > > > A bar makes a higher high. The next bar can have the same high or
> > > > a lower high but not, of course, a higher high. Then take the
> > > > lowest low of these two bars. Now, in order to actually qualify
> > > > that first bar as a swing high, we need a bar that *closes* lower
> > > > than either of the first two bars.
> > > >
> > > > The minimum number of bars required to define a high is,
> > > > therefore, three. However, theoretically, there's no limit to the
> > > > maximum number of bars although in practise it's never reached
> > > > the limit (:-).
> > > >
> > > > Having defined a swing high, we then look for a swing low which
> > > > is defined in exactly the same way but, er, the other way around.
> > > > You cannot have two SHs or two SLs in a row, the order must be
> > > > SH, SL, SH, SL, etc.
> > > >
> > > > Well, I thought it was easy until I tried programming it...! But
> > > > I'm sure I'm just missing one step of logic somewhere or other.
> > > >
> > > > I've be everso grateful if anyone could help out.
> > > >
> > > > Thanks.
> > > >
> > > > Cheers,
> > > > Ian
> > > >
> > >
> > >
> >
> >
>
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