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{we need a bar that *closes* lower than either of
> > the first two bars.}
If C < C[1] or C < C[2] then begin
IF H < SWINGHIGH(1,H,2,33)....
On Thu, 19 Dec 2002 16:37 +0000 (GMT Standard Time)
ianwaugh@xxxxxxxxx (Ian Waugh) wrote:
> Gosh, is this as difficult as my limited EL abilities think it is...?
>
> Cheers,
> Ian
>
> > Hi All,
> > I was wondering if someone a bit more versed in El than me
> > could help with this.
> >
> > I'm trying to define a swing point, let's say a high, but it's not
> > like a "standard" high that has a lower high on either side, I'd like
> > to define a Swing high like this:
> >
> > A bar makes a higher high. The next bar can have the same high or a
> > lower high but not, of course, a higher high. Then take the lowest
> > low of these two bars. Now, in order to actually qualify that first
> > bar as a swing high, we need a bar that *closes* lower than either of
> > the first two bars.
> >
> > The minimum number of bars required to define a high is, therefore,
> > three. However, theoretically, there's no limit to the maximum number
> > of bars although in practise it's never reached the limit (:-).
> >
> > Having defined a swing high, we then look for a swing low which is
> > defined in exactly the same way but, er, the other way around. You
> > cannot have two SHs or two SLs in a row, the order must be SH, SL,
> > SH, SL, etc.
> >
> > Well, I thought it was easy until I tried programming it...! But I'm
> > sure I'm just missing one step of logic somewhere or other.
> >
> > I've be everso grateful if anyone could help out.
> >
> > Thanks.
> >
> > Cheers,
> > Ian
> >
>
>
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