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Re: AW: back to the well again... parallel trend lines



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> Solution: P4 = (x3+x2-x1, y3+y2-y1)

Awww, that's too EASY...  :-)

Good point, Michael.  I got so caught up in trigonometry that I 
didn't think of the obvious approach.

That will produce a line from P3 to P4 at the same angle as the 
original P1-P2 line.  P3 will be one endpoint.  If you wanted the 
parallel line centered around P3, you could just add/subtract 1/2 the 
x2-x1 and y2-y1 values to the P3 location.

Gary