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So all you really need is an xaverage of myarray[0].
Try something like...
fact = 2/(len+1);
av = (1-fact)*av[1] + fact*myarray[0];
> No ! My array indexes in the new value at 0 and kicks out the last at 20 and
> moves everything down at the close of each bar. I am sure it can be done, it
> is just a little over my head. Thanks for your input.
--
Dennis
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