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Dans un courrier daté du 03/09/98 06:06:21 , vous avez écrit :
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| for k=10 downto 0 begin
| plot1[k](value1[k],"myStuff");
| plot2[k](value2[k],"myStuff");
| end;
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| Sincerely,
|
| Pierre Orphelin
| www.sirtrade.com
Pierre,
Is there a reason your example uses "k=10 downto 0" instead of "k=1 downto
0"?
What is the value of going more than the previous bar back?
And does this really correct a paint bar that was painted during Update
Every Tick, but then the condition became invalid by the completion of a
bar?
Thank you, >>
This solution has not been tested, only typed directly from the infamous
aol mailer.
Either the for "k=1 downto 0" will be sufficient to enforce repainting, or you
will need to increase k if it does not work for you (at the cost of computer
time).
I have note tested TS5 realtime, but from the ofline version, it seems that
refreshing the screen behaves diferently.
Sincerely,
Pierre Orphelin
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