Hi Brett
Sum(Function(X)>1,50)>0 is one way I can
think of but there are sure to be other ways as well. Since MS treats any number
other than zero as a logical true you could leave off the ">0" test and still
get the required result.
Regards
Roy
----- Original Message -----
Sent: Saturday, January 03, 2009 4:50
AM
Subject: Re: [EquisMetaStock Group] Re:
Quick checks
Good Morning --
I hope that someone can help me code the following in
Metastcok --
Function(x) is greater than +1 sometime within the past 50
days.
Function(X) can be either a standard Metastock indicator or
a label in a custom indicator.
Thanks, Brett
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