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Ticiano,
Helps if we know which Williams System you are looking at.
Preston
--- In equismetastock@xxxxxxxxxxxxxxx, "Ticiano Rêgo"
<ticianorego@xxx> wrote:
>
> I´m trying to develop a System Tester to verify the Bill Williams
System.
>
> There are 12 breakout conditions. ¨6 on the long side and 6 on the
short side.
>
>
> Long:
>
> up1=(H>Ref(H,-1) AND H>Ref(H,-2) AND H>Ref(H,1) AND H>Ref(H,2));
>
> up2=(H>Ref(H,-1) AND H>Ref(H,-2) AND H=Ref(H,1) AND H>Ref(H,2) AND
H>Ref(H,3));
>
> up3=(H>Ref(H,-1) AND H>Ref(H,-2) AND H>Ref(H,1) AND H=Ref(H,2) AND
H>Ref(H,3));
>
> up4=(H>Ref(H,-1) AND H>Ref(H,-2) AND H=Ref(H,1) AND H=Ref(H,2) AND
> H>Ref(H,3) AND H>Ref(H,4));
>
> up5=(H>Ref(H,-1) AND H>Ref(H,-2) AND H=Ref(H,1) AND H>Ref(H,2) AND
> H=Ref(H,3) AND H>Ref(H,4));
>
> up6=(H>Ref(H,-1) AND H>Ref(H,-2) AND H>Ref(H,1) AND H=Ref(H,2) AND
> H=Ref(H,3) AND H>Ref(H,4));
>
>
> Short:
>
> dn1=(L<Ref(L,-1) AND L<Ref(L,-2) AND L<Ref(L,1) AND L<Ref(L,2));
>
> dn2=(L<Ref(L,-1) AND L<Ref(L,-2) AND L=Ref(L,1) AND L<Ref(L,2) AND
L<Ref(L,3));
>
> dn3=(L<Ref(L,-1) AND L<Ref(L,-2) AND L<Ref(L,1) AND L=Ref(L,2) AND
L<Ref(L,3));
>
> dn4=(L<Ref(L,-1) AND L<Ref(L,-2) AND L=Ref(L,1) AND L=Ref(L,2) AND
> L<Ref(L,3) AND L<Ref(L,4));
>
> dn5=(L<Ref(L,-1) AND L<Ref(L,-2) AND L=Ref(L,1) AND L<Ref(L,2) AND
> L=Ref(L,3) AND L<Ref(L,4));
>
> dn6=(L<Ref(L,-1) AND L<Ref(L,-2) AND L<Ref(L,1) AND L=Ref(L,2) AND
> L=Ref(L,3) AND L<Ref(L,4));
>
>
>
>
> Does anyone already have done this ?
>
>
> Thanks,
>
> Ticiano
>
------------------------------------
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