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jtvinz,
Finally able to work on this and I believe this is what you want.
Basically, the value of the HHV is displayed up until the last 3
days, then it is held constant for the last 3 bars.
A:=HHV(H,15);
ValueWhen(1,Cum(1)<LastValue(Cum(1)-2),A);
If this is not what you want let me know.
Preston
--- In equismetastock@xxxxxxxxxxxxxxx, pumrysh <no_reply@xxx> wrote:
>
> jtvinz,
>
> Try this:
>
> valuewhen(1,cum(1)=cum(1)-3,hhv(h,15);
>
> I'm not in front of my computer right now but I think this is
right.
> Using the ref(hhv,h,15),-3) would not give you the current signal.
By
> using cum(1) we still have the current signal but will only use
the
> data from 3 days ago, which is what I think you want. Let me know
if
> this is not right.
>
> Hope this helps,
>
> Preston
>
>
>
>
> --- In equismetastock@xxxxxxxxxxxxxxx, "jtvinz" <jtvinz@> wrote:
> >
> > Hi Preston,
> >
> > Thank you. It means that the Highest High, excluding any value
> within
> > the last 3days. The equivalent of this in PCF (Personal
Criteria
> > Formulas) For TeleChart Software is MAXH15.3
> >
> > Thanks for your help.
> > jtvinz
> >
> >
> > --- In equismetastock@xxxxxxxxxxxxxxx, pumrysh <no_reply@> wrote:
> > >
> > > jtvinz,
> > >
> > > HHV(High,15) is the code for the highest high but I'm not sure
> what
> > > you mean by starting 3 days ago.
> > >
> > >
> > > Preston
> > >
> > >
> > >
> > > --- In equismetastock@xxxxxxxxxxxxxxx, "jtvinz" jtvinz@ wrote:
> > > >
> > > > Hi,
> > > >
> > > > I need help. How do I express the following in metastock
code?
> > > >
> > > > The Highest HIGH over a 15-day period beginning 3 days ago
> > > >
> > > > Thank you.
> > > > jtvinz
> > > >
> > > >
> > > >
> > > > [Non-text portions of this message have been removed]
> > > >
> > >
> >
> >
> >
> > [Non-text portions of this message have been removed]
> >
>
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