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Oops, this will only work if a pipsize is 1. Change it to
1/max(h-l,0.0000001)*(h>l)
to make it a bit more general. Note the problem with the earlier
version, if h-l=0.5, it would still substitute the 0.5 with 1 (the max
of 1 and 0.5 = 1) in the divisor.
Regards
MG Ferreira
TsaTsa EOD Programmer and trading model builder
http://www.ferra4models.com
http://fun.ferra4models.com
--- In equismetastock@xxxxxxxxxxxxxxx, mgf_za_1999 <no_reply@xxxx> wrote:
> Even though you do something like
>
> if(h<>l,1/(h-l),0)
>
> MSFL will still evaluate the expression, regardless of the fact that
> it will not be returned. This has been discussed before, try
> something like
>
> 1/max(h-l,1)*(h>l)
>
> which will ensure that the divisor is always positive and also that
> you get a zero when h=l from the ... *(h>l) portion.
>
> Regards
> MG Ferreira
> TsaTsa EOD Programmer and trading model builder
> http://www.ferra4models.com
> http://fun.ferra4models.com
>
>
> --- In equismetastock@xxxxxxxxxxxxxxx, Tiunan <tiunan@xxxx> wrote:
> > Hello,
> >
> > I have this message :
> > The following maths errors occured during the calculation of ...
> > Division by zero 29.
> > My program is the following (really simple):
> > 1/(hight-low)
> > My solution is:
> > if ((H-L)=0,0,1/(H-L))
> > or I have this solution:
> > If(H<>L,1/(H-L),0)
> >
> > In fact I have always this message.
> > Any help will be appreciate (why 29 ?)
> >
> > Thank you for all
> > Regards Tiunan.
> >
> >
> >
> >
> >
> >
> >
> >
>
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>
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