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Jose,
Yes I'am blind it seems lol:) Thanks for pointing it out to me
Jose <josesilva22@xxxxxxxxx> wrote:
Andrew, I've put it further down in the "System/signal indicators"
section, fifth indicator down there, "EMA x3 crossovers" link.
http://www.metastocktools.com/index.html#metastock
jose '-)
Or, to make things easier:
==============================
EMA - triple crossover signals
==============================
---8<---------------------------
{ Triggers Long (+1) & Short (-1) signals at
crossover of triple EMAs within x periods }
{ http://www.metastocktools.com }
pdsLong:=Input("Long crossover within x periods",1,252,2);
pdsShort:=Input("Short crossover within x periods",1,252,3);
short:=Input("short EMA periods",1,252,5);
medium:=Input("medium EMA
periods",2,1008,10);
long:=Input("long EMA periods",3,2520,20);
x:=Input("use Open=1 High=2 Low=3 Close=4 Volume=5 P=6",1,6,4);
x:=If(x=1,O,If(x=2,H,If(x=3,L,If(x=5,V,If(x=6,P,C)))));
goLong:=
Alert(Cross(Mov(x,short,E),
Mov(x,medium,E)),pdsLong)
AND
Alert(Cross(Mov(x,medium,E),
Mov(x,long,E)),pdsLong);
goShort:=
Alert(Cross(Mov(x,medium,E),
Mov(x,short,E)),pdsShort)
AND
Alert(Cross(Mov(x,long,E),
Mov(x,medium,E)),pdsShort);
goLong-goShort
---8<---------------------------
--- In equismetastock@xxxxxxxxxxxxxxx, Andrew Slemko <andrew_slemko@xx
..> wrote:
> Jose,
>
> I was looking on the below link for the mentioned EMA indicator -
> I must be blind because I did not find one titled "triple EMA
> Crossover" (bow tie) tie systems. What name does it go by?
> Exponential Moving Average v2.2? EMA - improved Exponential Moving
> Average with
crossover signals output choice, is that the one
> correct?
>
> Andrew
>
>
> Jose <josesilva22@xxxx> wrote:
>
> Try the "EMA x3 crossovers" - triple EMA crossover (bow tie) system
> signals (Long/Short) at:
> http://www.metastocktools.com/#metastock
>
> jose '-)
>
>
> --- In equismetastock@xxxxxxxxxxxxxxx, "sharksfinn2001" <dougley@xxx
.> wrote:
>
> Hi I am new to Metastock formulae language and am having difficulty.
> Can anyone help to code this for me using the cross function.
>
> A cross of a 5 ema 10 ema and 15 ema.
>
> Many thanks for your patience.
> Doug.
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