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Lynn, it's very unlikely that an exploration will find the first event
of a common occurrence happening today, unless you load a small number
of exploration bars such as 100 or so.
In any case, just put the whole formula in the exploration filter.
---8<-------------------------
pds1:=10;
pds2:=20;
Normal:=Cross(Mov(MACD(),pds1,E),Mov(MACD(),pds2,E));
firstNormal:=Normal AND Cum(Normal)=1;
Reverse:=Cross(Mov(MACD(),pds2,E),Mov(MACD(),pds1,E));
firstReverse:=Reverse AND Cum(Reverse)=1;
firstNormal OR firstReverse
---8<-------------------------
jose '-)
--- In equismetastock@xxxxxxxxxxxxxxx, "lynn14344" <darisr@xxxx>
wrote:
> Thanks, Jose for the reply.
> Can you help me to find a formula for the first time crossover for
> exploration purposes. I don't want it on the chart because I scan it
> on NYSE stocks and there are about 3000 stocks. So I need to do an
> exploration to shorten my daily homework. The previous formula of
> mine shows also when the crossover turns down and I only want one
> formula when the criteria turns up.
>
> Is there a possibility of helping me here. maybe you could look at
> my initial formula and sewhat I really mean.
>
> Thank you very much. Please let me know if you don't understand what
> I'm actually looking for.
>
>
>
>
>
>
> --- In equismetastock@xxxxxxxxxxxxxxx, "Jose" <josesilva22@xxxx>
> wrote:
> >
> > > Jose- Firstly I just wondering why is your method or formula
> written
> > > in a lengthy format.
> >
> > If you mean the pds1/pds2 variables, that's done for flexibility
> > purposes.
> > If you mean the lengthy variable names, that's done for clarity
> > purposes.
> > If you mean lengthy code, I can't see how it can be abbreviated
> > further than this:
> >
> > ---8<-------------------------
> >
> > pds1:=10;
> > pds2:=20;
> >
> > Normal:=Cross(Mov(MACD(),pds1,E),Mov(MACD(),pds2,E));
> > firstNormal:=Normal AND Cum(Normal)=1;
> >
> > Reverse:=Cross(Mov(MACD(),pds2,E),Mov(MACD(),pds1,E));
> > firstReverse:=Reverse AND Cum(Reverse)=1;
> >
> > firstNormal-firstReverse
> >
> > ---8<-------------------------
> >
> >
> > > Secondly, I still have symbols turning up which is in the
> opposite
> > > value that is to say when the 20 day crosses the 10 day. So it
> looks
> > > like its pointing down. What I really want is the 10 day crosses
> the
> > > 20 day and it looks like pointing up.
> >
> > In your original post you asked for both bullish AND bearish
> patterns:
> >
> > "I'm looking at the FIRST time crossover( when moving ave
> > for 10 days is greater than the 20 days) based on the formula
below
> > but it also shows results based on the reverse form( moving ave 20
> > days greater than 10 days)."
> >
> > If you wish to find just the FIRST bullish pattern, use the code
> above
> > - it plots +1 for the FIRST bullish pattern, and -1 for the FIRST
> > bearish one. Plot it as an indicator first, so you can understand
> how
> > it works. This code won't work in an exploration because of the
> > nature of your request (FIRST events).
> >
> >
> > jose '-)
> >
> >
> > --- In equismetastock@xxxxxxxxxxxxxxx, "lynn14344" <darisr@xxxx>
> > wrote:
> > >
> > >
> > > Thank you guys for the reply.
> > > Harry- I tried what you mentioned but its troublesome to look at
> the
> > > chart individually because once I have that first cross over on
> the
> > > daily or 60 minutes than I would like to use the same last
> explored
> > > values to do for the weekly.
> > > So your suggestion doesn't help. Is there another way to just
> look
> > > at the first crossover.
> > >
> > > Jose- Firstly I just wondering why is your method or formula
> written
> > > in a lengthy format.
> > >
> > > Secondly, I still have symbols turning up which is in the
> opposite
> > > value that is to say when the 20 day crosses the 10 day. So it
> looks
> > > like its pointing down. What I really want is the 10 day crosses
> the
> > > 20 day and it looks like pointing up.
> > >
> > > Is there a way for me solve this problem because I'm back where
> I
> > > started with my initial exploration formula.
> > >
> > > Thank you very much for you time in looking at this. I really
> hope
> > > someone can help me out.
> > > Thank you again
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