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Hi Jose
> Roy, both posted Linear Regression Slope formulae outputs are so close
> to the MetaStock canned LRS version, that in my view it isn't worth
> the extra code complexity and processing overheads.
Interesting. I need to think about the signifcance of this. My thinking is that the linear
regression of a line is different from the line itself, and therefore the slope of a line should be
different from the slope of the linear regression of that line. Have I got it wrong? Perhaps I
should do some of my own testing rather than go with unfounded assumptions.
Roy
> ---8<------------------
> pds:=Input("Periods",5,50,10);
> LinRegSlope(P,pds)
> ---8<------------------
>
> ---8<------------------
> A:=Tema(C,75);
> pds:=10;
> LinRegSlope(A,pds)
> ---8<------------------
>
> jose '-)
>
>
> --- In equismetastock@xxxxxxxxxxxxxxx, "Roy Larsen" <rlarsen@xxxx>
> wrote:
> > Bill
> >
> > I have this formula for "slope of line".
> >
> > {Slope of Line}
> > Periods:=Input("Periods",5,50,10);
> > Slope:=((Sum(Cum(1)*P,Periods))-
> > (Sum(Cum(1),Periods)*Sum(P,Periods)/Periods))/
> > ((Sum(Power(Cum(1),2),Periods))-
> > (Power(Sum(Cum(1),Periods),2)/Periods));
> > Slope;
> >
> > Here's virtually the same thing applied to a 75 period Tema of
> CLOSE.
> >
> > {Slope of Tema}
> > A:=Tema(C,75);
> > Pds:=10;
> > Slope:=((Sum(Cum(1)*A,Pds))-
> > (Sum(Cum(1),Pds)*Sum(A,Pds)/Pds))/
> > ((Sum(Power(Cum(1),2),Pds))-
> > (Power(Sum(Cum(1),Pds),2)/Pds));
> > Slope;
> >
> > I'm unaware or who the author is but think I picked these up from
> the Guppy site ages ago.
> >
> > Roy
>
>
>
>
>
>
> Yahoo! Groups Links
>
>
>
>
>
>
>
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