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RE: [Metastockusers] RE:Re: Bar Count since certain date



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<FONT face=Tahoma 
size=2>-----Original Message-----From: Robin Hood 
[mailto:robinhood@xxxxxxxx] Sent: Monday, January 06, 2003 3:11 
PMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re: 
[Metastockusers] RE:Re: Bar Count since certain date
Hi Lionel
 
As acutely you note, my old books of mathemathics lie behind Peanuts' 
comics, I admit..
 
I don't understand perfectly what you mean. This is the only certain thing. 
For this, reading one of these books, I found some little examples and now I'll 
report here. Maybe you can help me with the contents.
 
Now, a parabola (I translate with my own hands.. :-( ) is the geometrical 
place of equidistant points from a fixed point (fuoco = fire in italian) 
and from a fixed straight (retta direttrice = straight director 
?).<FONT face=Arial 
size=2> . 
 
The general formula for the parabola is:
y = ax^2 + bx +c
where "a", "b", "c" are arbitrary constants and "a" not equal to 
zero.
 
Let's determine a, b, c of the general formula (that's let's determine the 
whole formula) for the following three points:
A (-1,10)
B (-2,1)
C (-1/2,6)
 
We have to resolve the system:
10 = a - b - c
1 = 4a + 2b + c
6 = 1/4 a - 1/2 b +c
 
Resolving, we have that:
a = 2
b = -5
c = 3
That's the formula of our parabola:
y = 2x^2 - 5x + 3
 
(at this point, we could also find the coordinates of fire, vertix, 
simmetry axis by using their fixed relationship with the parameters)
 
Circle is a particular case of the ellypse: the geometrical place for which 
is constant the sum of distances from two fixed points (fires). IN the circle 
case, the fire have the same coordinates. Something different from the parabola 
(as different is its formula...).
 
It's time to take in hand my comics, now. Their meant, 
fortunately, don't change with latitudes :-)
 
 
 
For who understands Italian or has the patience of translate... here is a 
link where focus mi purpose
<A 
href="http://www.performancetrading.it/AT/Evolventi/EPIndex.htm";>http://www.performancetrading.it/AT/Evolventi/EPIndex.htm
 
Exist also a program that makes parabolas...
<A 
href="http://www.tk-it.com/index.htm";>http://www.tk-it.com/index.htm
 
 
best regards
 
    robin
 
 
 
<BLOCKQUOTE 
style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
  ----- Original Message ----- 
  <DIV 
  style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
  Lionel 
  Issen 
  To: <A 
  title=Metastockusers@xxxxxxxxxxxxxxx 
  href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
  
  Sent: Sunday, January 05, 2003 11:00 
  PM
  Subject: RE: [Metastockusers] RE:Re: Bar 
  Count since certain date
  
  <FONT face=Arial 
  size=2>Robin:
  <FONT face=Arial 
  size=2> 
  You're English is 
  fine, it's certainly better than my Italian, which is 
zero.
  <FONT face=Arial 
  size=2> 
  I think that I 
  understand what you are trying to say. The problem may be is that you 
  don't  understand the relationship between mathematics and curve fitting 
  (sometimes called statistics). 
  <FONT face=Arial 
  size=2> 
  At the web 
  sites, the examples are so set up that the the parabola is 
  predefined and predetermined. Two of the points are at the end of the latus 
  rectum, and the third point is at the vertex. If you take 3 points so that the 
  the perpendicular bisector of the line joining the first and third points does 
  not intersect the middle point. then these 3 points wont define a 
  parabola, they will define a circle.
  <FONT face=Arial 
  size=2> 
  The figures at the 
  web site predefines the parabola.  Referring to the figure at the 3rd web 
  site. in general
  FP1 <> 
  P1D1
  <FONT face=Arial 
  size=2> 
  As I wrote 
  earlier, data points do not lie on nice smooth curves. When curve fitting 
  data, we have to decide what kind of curve fits the data and then try to fit 
  such a curve to the data. For these reasons we need many more points 
  than the minimum needed to define the curve.
  <FONT face=Arial 
  size=2> 
  If you have access 
  to an academic library look up some books on curve fitting.  Try to find 
  some that were written before the days of computers.  Let me know what 
  you find.
  <FONT face=Arial 
  size=2> 
  <FONT face=Arial 
  size=2>Lionel
  <FONT face=Arial 
  size=2> 
  <FONT face=Arial 
  size=2> 
  
  
  <FONT 
  face=Tahoma size=2>-----Original Message-----From: Robin Hood 
  [mailto:robinhood@xxxxxxxx] Sent: Sunday, January 05, 2003 9:51 
  AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re: 
  [Metastockusers] RE:Re: Bar Count since certain date
  Lionel,
   
  my bad English doesn't help us... :-)
   
  Look at rhis site where there are a full description of what you already 
  know, I think
  <A 
  href="http://schools.spsd.sk.ca/mount/Hoffman/MathC30/Parabola/parabola.htm#trinomial";>http://schools.spsd.sk.ca/mount/Hoffman/MathC30/Parabola/parabola.htm#trinomial
   
   
  I find this about autocad (I don't use it)
  <A 
  href="http://xarch.tu-graz.ac.at/autocad/news/lisp_progs/msg00013.html";>http://xarch.tu-graz.ac.at/autocad/news/lisp_progs/msg00013.html
   
  and anyway the results of this search say that wee need three points for 
  building a parabola (by solving a system of equations I remember - maybe :-) 
  )
   
   
  <A 
  href="http://www.google.it/search?q=build+parabola+three+points&hl=it&lr=&ie=UTF-8&oe=UTF-8&start=0&sa=N";>http://www.google.it/search?q=build+parabola+three+points&hl=it&lr=&ie=UTF-8&oe=UTF-8&start=0&sa=N
   
   
  I hope your math knowledge is better than mine and unserstand what I'd 
  like to say.
   
   
   
      robin
   
   
   
  <BLOCKQUOTE 
  style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
    ----- Original Message ----- 
    <DIV 
    style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
    Lionel 
    Issen 
    To: <A 
    title=Metastockusers@xxxxxxxxxxxxxxx 
    href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
    
    Sent: Sunday, January 05, 2003 3:13 
    PM
    Subject: RE: [Metastockusers] RE:Re: 
    Bar Count since certain date
    
    <FONT face=Arial 
    size=2>Robin:
    <FONT face=Arial 
    size=2> 
    Can you direct 
    me to the portion of the cited web site where it says that 3 points are 
    sufficient to define a parabola? Three points would be sufficient to define 
    a parabola if you know the semi latus rectum (factor F 
    below).
    <FONT face=Arial 
    size=2> 
    Please bear with 
    me. While both the circle and the parabola are conic sections their 
    equations are different.
    <FONT face=Arial 
    size=2> 
    Equation of 
    Circle : X**2 + Y**2 = R**2    R is the 
    radius
    <FONT face=Arial 
    size=2> 
    Equation of 
    parabola: Y**2 = 
    4FX            F is 
    the semi latus rectum
    <FONT face=Arial 
    size=2> 
    Here is a little 
    exercise you can do.  All you need are two pieces of paper, a 
    pencil, a compass, a straight edge (a ruler will do) and maybe an 
    eraser.
     
    Place 3 points 
    on a piece of paper, they must not be on a straight line. Call them A, B, 
    and C. Draw the lines A-B and B-C. Bisect these 2 lines and draw the 
    perpendicular bisectors. the bisectors will meet at the center of the 
    circle. Next select any other 3 points on the circle and repeat this little 
    exercise.  These bisectors will also meet at the center of the 
    circle.  Before the days of electronic navigation, the basis 
    of this method was used by navigators near shore or in narrow 
    channels to locate the position of the vessel.
    <FONT face=Arial 
    size=2> 
    If you draw a 
    parabola and select two or more sets of three points on the 
    parabola and repeat the exercise, the bisectors will not meet at the same 
    place.
    <FONT face=Arial 
    size=2> 
    If you have any 
    further questions please write me privately
    <FONT face=Arial 
    size=2> 
    <FONT face=Arial 
    size=2>Lionel
    <FONT face=Arial 
    size=2> 
    <FONT face=Arial 
    size=2> 
    <FONT face=Arial 
    size=2> 
    
    
    <FONT 
    face=Tahoma size=2>-----Original Message-----From: Robin Hood 
    [mailto:robinhood@xxxxxxxx] Sent: Sunday, January 05, 2003 4:51 
    AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: Re: 
    [Metastockusers] RE:Re: Bar Count since certain date
    Hi Lionel
     
    Three points are sufficient as parabola is made by tho points 
    equidistanced (? in english ?) form another one.
    <A 
    href="http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html";>http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabola.html for 
    examples (by google).
     
    Here is a chart form an Italian site which I don't name because of 
    netiquette (I think...). They build a parabola from three points, in effect. 
    It's the same effect I'd like to reproduce with Metastock... but the trouble 
    are the input dates (x coordinates) :-(
     
     
     
        robin
     
     
    <BLOCKQUOTE 
    style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
      ----- Original Message ----- 
      <DIV 
      style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
      Lionel 
      Issen 
      To: <A 
      title=Metastockusers@xxxxxxxxxxxxxxx 
      href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
      
      Sent: Saturday, January 04, 2003 4:57 
      PM
      Subject: RE: [Metastockusers] RE:Re: 
      Bar Count since certain date
      
      Three points 
      always define a circle. I think that you need at least 4 points to 
      define a parabola. When curve fitting a parabola you need more than 4 
      points as data points always have some noise, they don't fall on a nice 
      smooth curve.
       
       
      
      
      <FONT 
      face=Tahoma size=2>-----Original Message-----From: Robin Hood 
      [mailto:robinhood@xxxxxxxx] Sent: Saturday, January 04, 2003 
      8:25 AMTo: Metastockusers@xxxxxxxxxxxxxxxSubject: 
      Re: [Metastockusers] RE:Re: Bar Count since certain 
      date
      Hi Group
       
      Thanks to Spyros for his formula.
       
       
      In order to build a parabolic trend-line, I need three points 
      (geometry requires it). It means three x,y (date, 
      price) coordinates.
       
      The problem is that metastock accepts only six inputs (in oder to 
      define dates I need 3+3+3=9 inputs :-( ).
       
      Is there another way to make this?
       
      Now, the formula inputs are as follows, but I'd like to 
      change the numbers with dates since I don't understand very well and 
      immediately their sequence
       
      x1:=Input("point 1 : x1",-100000000,100000000,0);y1:=Input(" 
      y1",-100000000,100000000,0);x2:=Input("point 2 : 
      x2",-100000000,100000000,0);y2:=Input(" 
      y2",-100000000,100000000,0);x3:=Input("Point 3: 
      x3",-100000000,100000000,0);y3:=Input(" 
      y3",-100000000,100000000,0);
       
       
       
      Thanks in advance, Robin
       
       
      <BLOCKQUOTE 
      style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
        ----- Original Message ----- 
        <DIV 
        style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black">From: 
        SR 
        To: <A 
        title=Metastockusers@xxxxxxxxxxxxxxx 
        href="mailto:Metastockusers@xxxxxxxxxxxxxxx";>Metastockusers@xxxxxxxxxxxxxxx 
        
        Sent: Saturday, January 04, 2003 
        2:24 PM
        Subject: [Metastockusers] RE:Re: 
        Bar Count since certain date
        bruneski came up with a variation of my approach 
        which is corrects somefailures of my version.So I suggest trying 
        this 
        one:{BarsSinceDate}d:=Input("Day",1,31,1);m:=Input("Month",1,12,1);y:=Input("Year",1920,2030,2002);mydate:= 
        10000*y + 100*m + d;date:= 10000*Year() + 100*Month() + 
        DayOfMonth();count:=BarsSince(mydate<=date); {use '<' if first 
        day is not to becounted}count:=count + 
        Cum(If(count=0,1,0));countTo unsubscribe 
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