Re: EasyLanguage to Metastock conversion

["Brooke" <brookelise@xxxxxxxx>]

Corey:

I don't think that'll do the job, because the formulas are self-referential,
or recursive. Did you get values with it? If so, you're working with a later
version of Metastock than I am.

I would have thought that you'd need to use PREV. I don't get anything with
this in Metastock, for example:

Value1:=Ref(Value1,-1) + C;
Value1;

What that formula would be trying to say is:

Value1:=PREV +C;
Value1;

The first line in the formula would be this, I think:

Value1:=0.088*ref(PREV,-6) +C;

But the Easy Language formula requires two PREV's in this line:

Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];

It might be translated as:

Value2:= 1.2*ref(PREV,-6) - 0.7*ref(PREV,-12) + Value1 - ref(Value1,-6) ;

Except that

a) PREV now refers back to the other PREV in the line, I think, and

b) I get an "Add Overflow" message with that formula.

So it would have to be broken down in some way so that there was only one
PREV in the line.

Something like this, though this still won't do it. I'd have to have an
EasyLanguage program to compare values.

Value1:=0.088*ref(PREV,-6) +C;
Value2a:= 1.2*ref(PREV,-6)+ (Value1 - ref(Value1,-6)) ;
Value2b:= 0.7*ref(PREV,-12)+(Value1 - ref(Value1,-6)) ;
Value2:=Value2a +Value2b;

But who knows? Maybe I'm wrong, and newer versions of Metastock can do
recursive formulas without PREV.

----- Original Message -----
From: "C.S." <csaxe@xxxxxxxxxxx>
To: <metastock@xxxxxxxxxxxxx>
Sent: Monday, March 05, 2001 4:55 PM
Subject: Re: EasyLanguage to Metastock conversion


> OK,
>     I'll take a stab at this. Please chime in if I'm wrong, as I can learn
> from this too.
>
> Value1:=C + 0.088 * Ref(Value1,-6);
> Value2:=Value1 - Ref(Value1,-6) + 1.2*Ref(Value2,-6) -
0.7*Ref(Value2,-12);
> Ref(Value2,-12) - 2*Ref(Value2,-6) + Value2
>
> Although the PREV function could have been used, I didn't because it tends
> to slow computation.
> -Corey
>
> ----- Original Message -----
> From: "Jeff Haferman" <haferman@xxxxxxxxxxxxxxxxxxxxxxx>
> To: <metastock@xxxxxxxxxxxxx>
> Sent: Sunday, March 04, 2001 5:03 PM
> Subject: EasyLanguage to Metastock conversion
>
>
> >
> > I've got some code I'm trying to convert to Metastock...
> > it's written in EasyLanguage.
> >
> > I've got:
> >
> > Value1 = Close + 0.088*Value1[6];
> > Value2 = Value1 - Value1[6] + 1.2*Value2[6] - 0.7*Value2[12];
> > D = Value2[12] - 2*Value2[6] + Value2;
> > Plot1(D,"D");
> >
> > Is there an easy way to write this as a Metastock indicator?
> > For example, Value1[6] means the value of Value1 6 bars ago.
> > But Value1 is defined recursively, so I'm not sure
> > how this can be done in Metastock.
> >
> >
> >
>
>