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Don't know what is going on, tried to sent
this already for the 3 times to the list.
will sent chart on other message
Thanks a million, it's more than normal that I try to code the MS part
myself. Although I hope that you can correct me when I make a
mistake.The original code is way down in this message, see below. For the
example I took the QQQ sinds 01/01/2000.
As you can see I converted to HTML format so I can
work with colors, hope you support it. I included the steps and the formula, so
MAYBE someone can learn of it. (I HOPE it correct)
n:=Input("Time
Periods",1,1000,10);dif:=Sum(Abs(CLOSE-Ref(CLOSE,-1)),n);signal:=Abs(CLOSE-Ref(CLOSE,-n));Efratio:=signal/dif;Efratio
Thanks Kent
Mickey>
-----Original Message-----> From: owner-metastock@xxxxxxxxxxxxx>
[<A
href="mailto:owner-metastock@xxxxxxxxxxxxx";>mailto:owner-metastock@xxxxxxxxxxxxx]On
Behalf Of Kent Rollins> Sent: maandag 27 november 2000 17:44> To:
metastock@xxxxxxxxxxxxx> Subject: Re: Easy language to MS translation
HELP>>> I will help you, but you will have to do the MS
coding.>> Step 1: compute the efficiency ratio.>>
dif = @AbsValue(price - price[1])
<FONT color=#0000ff
size=3>dif:=Sum(Abs(CLOSE-Ref(CLOSE,-1)),n);<FONT
size=2>>> This means 'dif' equals the absolute value of 'price'
minus the prior> 'price'. Let's assume 'price' is 'close' so create
a MS statement to> compute that.>> signal = @AbsValue(price
- price[period])
n:=Input("Time Periods",1,1000,10);
<FONT color=#0000ff
size=3>signal:=Abs(CLOSE-Ref(CLOSE,-n));>> This means
'signal' equals the absolute value of 'price'> minus 'price N
bars> ago'. Again, assume 'price' is 'close' and 'N' should be
an> input into the> equation. Let's assume N = 10.
Create an MS statement for that.>> noise =
@summation(dif,period)
this step I included in the first
formula by adding SUM(...,n)>> Simple enough: add up the
value of 'dif' over the last N bars.>> efratio = signal /
noise
<FONT color=#0000ff
size=3>Efratio:=signal/dif;Efratio>> Again,
self-explanatory. This is the Kaufman Efficiency> Ratio which is
used> as an input into the Kaufman Adaptive Moving Average which
we> will compute> next. Show me a plot of the Efficiency
Attachment:
Description: "Kent>"
Attachment:
Description: "Ratio in Metastock and we will> proceed to the next step.>> "
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