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Define iterations...
There are some limits in the formula language, but until I understand your
definition of iterations, I cannot confirm or deny such a limitation exists.
As for the Ref() function itself, I am not aware of any problems or
limitations regarding the magnitude of the number that can be used in the
second argument.
Ken Hunt
Programming Manager
Equis International
-----Original Message-----
From: Lionel Issen [mailto:lissen@xxxxxxxxx]
Sent: Tuesday, September 12, 2000 5:26 PM
To: metastock@xxxxxxxxxxxxx
Subject: Re: a new problem with Ref()
Guy:
If I understand what you are trying to do, here's a suggestion.
There is a limit on the number of iterations that Metastock can handle in a
single formula.
One way around this might be to break up your iterations into blocks of not
more than 8 iterations, then combine these into one formula.
The Metastock formula language is distinctly limited.
It may be easier to do this in Excel or VB or TAS.
Lionel Issen
lissen@xxxxxxxxx
----- Original Message -----
From: Guy Tann <grt@xxxxxxxxxxxx>
To: Metastock User Group <metastock-list@xxxxxxxxxxxxx>
Sent: Tuesday, September 12, 2000 5:30 PM
Subject: a new problem with Ref()
> List,
>
> Well I've programmed my way around the last problem, but I just hit
another
> snag.
>
> Is there a limit in using the Ref() function?
>
> I have a variable called MXX. I am manipulating it in a simplistic manner
> and the first 8 worked great. When I get to the ninth iteration, it quits
> working.
>
> XEIGHT:= ( MXX - Ref( MXX , -8 ) ) / 8; This one works correctly
> XNINE:= ( MXX - Ref( MXX , -9 ) ) / 9; This one doesn't work!
>
> Actually, numbers one through eight work fine. Nine and ten don't work
and
> I haven't finished checking eleven through twenty yet. I assume there's
> something in the manual I missed, so any help would be appreciated.
>
> Thanks,
>
> Guy
>
> " When I die, I want to go peacefully like my grandfather did, in his
sleep.
> Not yelling and screaming like the passengers in his car."
>
>
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