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Many thanks to HHP, J., Glen and Martin for the DYNAMITE support on this
question. Much obliged!
Good trades and best regards,
Philip
HHP wrote:
> Philip,
>
> You can use binary logic. Any True/False statement evaluates to 1 when
> true and to 0 when false. Assuming you define a rising trend as having
> a value greater than the previous day, then:
>
> Mov(C,21,E) > Ref(Mov(C,21,E),-1) would such a statement.
>
> (ADX(13) > Ref(ADX(13),-1)) = 0 would test for the ADX not rising.
>
> Note also that you can combine True/false statements mathematically:
>
> (Mov(C,21,E) > Ref(Mov(C,21,E),-1)) * (ADX(13) > Ref(ADX(13),-1)) is the
> same as an AND statement: it evaluates to true (1*1=1) only whan both
> components are true, otherwise to 0.
>
> (Mov(C,21,E) > Ref(Mov(C,21,E),-1)) + (ADX(13) > Ref(ADX(13),-1)) = 1
> would be true when only one component is true, but false when neither or
> both are true.
>
> (Mov(C,21,E) > Ref(Mov(C,21,E),-1)) + (ADX(13) > Ref(ADX(13),-1)) >= 1
> would be false only when both components are false.
>
> Even a statement "If A then B, else C" can be written (A*B) + (1-A)*C.
>
> HHP
> ==========================
>
> Philip wrote:
> >
> > When writing Metastock formula syntax, is there a way to specify that a
> > condition should NOT obtain?
> >
> > Examples:
> >
> > EMA(21) is rising, but the ADX(13) ISN'T.
> >
> > Such an such an oscillator is above (say) 80, but this other set of
> > circumstances (expanding on it now) is NOT the case.
> >
> > Or must I spell out which conditions I want the second element/elements to
> > fulfill in terms of "true?"
> >
> > Philip
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