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[amibroker] Re: how to code this condition



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right......
but this time around i have no clue how to combine these 2 conditoins

BarsSinceCCICrossed200=BarsSince(Cross(array,200));

cciless90=cross(90,array);
now how do i check to see if cciless90 for bars since BarsSinceCCICrossed200





--- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70" <sidhartha70@xxx> wrote:
>
> I don't understand your explanation.
> However, the easiest way to check and code this is to find some appropriate data, and plot the various elements that will make up your final condition... by doing this you can correctly build the correct logic and order.
> 
> 
> --- In amibroker@xxxxxxxxxxxxxxx, "murthysuresh" <money@> wrote:
> >
> > that will not work. example data is as below
> > 
> > 210	200	270	220	190	160	100	90	110		valid
> > 210	200	270	220	190	160	100	89	110		invalid
> > 
> > 
> > 
> > --- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70" <sidhartha70@> wrote:
> > >
> > > Just a guess but try this...
> > > 
> > > BarsSinceCCICrossed200andBelow90= BarsSince(BarsSinceCCICrossed200 AND Cross(90,array));
> > > 
> > > --- In amibroker@xxxxxxxxxxxxxxx, "murthysuresh" <money@> wrote:
> > > >
> > > > the CCI should have crossed 200. Once it crossed 200, it should have have crossed below 90.
> > > > i got the first one right as below
> > > > array = CCI( 20 );
> > > > BarsSinceCCICrossed200=BarsSince(Cross(array,200));
> > > > 
> > > > without using a for loop, how can i code the second condition.
> > > > Once it crossed 200, it should have have crossed below 90.
> > > >
> > >
> >
>




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