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SelectedValue() works Bill... Thanks.
However, the problem I'm having is that I'm using this in AFL code and
I want it to complete the historical array if you like, not just off a
SelectedValue() but with each value of Sum(x,range) as ir changes...
which it's looking like is not possible.
Horribly I might have to use a loop. Errrgg.
--- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70" <sidhartha70@xxx> wrote:
>
> Nope, I've tried it Bill...
>
> I get an Error 5, Argument #3 has incorrect type on the ValuneWhen()
> line...
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "wavemechanic" <timesarrow@> wrote:
> >
> > Have you tried it or are just "not sure"? Works for me and can move
> to any bar and get the "selectedvalue". If in doubt use
> selectedvalue(sum()).
> > ----- Original Message -----
> > From: sidhartha70
> > To: amibroker@xxxxxxxxxxxxxxx
> > Sent: Tuesday, January 13, 2009 6:01 AM
> > Subject: [amibroker] Re: Finding the last true value in an array...
> >
> >
> > Actually Bill, not sure this works... since the 3rd argument in
> > ValueWhen() is required to be a number and not an array.
> > Could use LastValue() to turn it into a number, but of course this
> > only returns the value from the right hand edge of the chart...
so it
> > wouldn't work historically... which is what I need.
> >
> > Any thoughts...?
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, "wavemechanic" <timesarrow@>
wrote:
> > >
> > > How about this?
> > >
> > > x = condition that generates your 1,0 array
> > > y = sum(x, range)
> > > z = valuewhen(x, barindex(), y)
> > > position in array = lastvalue(barindex()) - z + 1
> > >
> > > Bill
> > > ----- Original Message -----
> > > From: sidhartha70
> > > To: amibroker@xxxxxxxxxxxxxxx
> > > Sent: Monday, January 12, 2009 6:33 PM
> > > Subject: [amibroker] Re: Finding the last true value in an
> array...
> > >
> > >
> > > Sorry Barry... my terminology is confusing...
> > >
> > > Lets say I have an array that has only true or false values in
> it...
> > >
> > > Lets say the last 10 value of this array are as follows, from x
> > > intervals ago until now...
> > >
> > > 0,1,0,0,1,0,0,1,0,0
> > > x.................Now
> > >
> > > Now, obviously, BarsSince(array) will return a value of 2...
> i.e. the
> > > last true value was 2 intervals ago.
> > >
> > > However, the value I'm trying to get is the last value of true
> in the
> > > above x elements of the array... so I want an expression that
> returns
> > > 8 for the above array (i.e. 8 intervals back is the last
value of
> > > true). Any ideas...?
> > >
> > > Hopefully that's clearer now.
> > >
> > >
> > > --- In amibroker@xxxxxxxxxxxxxxx, "Barry Scarborough"
<razzbarry@>
> > > wrote:
> > > >
> > > > What are your trying to do? HHV gives the value of the
> highest high
> > > > over the period you enter in x. If you want to find how
far back
> > that
> > > > is you can use
> > > >
> > > > bs = BarsSince(H == HHV(H, 10));
> > > > // the next line prints the num bars back and the high of
> that bar
> > > > printf(NumToStr(bs, 1.0) + " High " + NumToStr(HHV(H, 10),
> 1.2));
> > > >
> > > > If you want to find the value of the other things bs bars
> ago then
> > > > you can
> > > > // use the following. This applies to any array
> > > > lastHigh = ref(High, - bs);
> > > > // this is another way to see the results that shows the
> high value
> > > > Plot(lastHigh, "high bars ago", colorBlack);
> > > > Plot(Ref(C, -bs), "close bars ago", colorblue);
> > > > Plot(Ref(MA(C, 10), -bs), "MA(10) value bars ago",
colorGreen);
> > > > // then look at what valuewhen returns
> > > > Plot(ValueWhen(H == HHV(H, 10), H, -1), "ValueWhen",
colorRed);
> > > >
> > > > bsolutely the last thing you want to do is start using loops,
> > such as
> > > > for loops, to extract data from ABs arrays. Your code will
> be much
> > > > cleaner and faster if you use straight AFL.
> > > >
> > > > Your terminology true value is confusing. The value in an
> array is
> > > > the true value. Do you mean what was the value when the
> > condition was
> > > > true?
> > > >
> > > > Barry
> > > >
> > > >
> > > >
> > > > --- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70"
<sidhartha70@>
> > > > wrote:
> > > > >
> > > > > Graham,
> > > > >
> > > > > I'm trying to get my head around that code right now...
> but first
> > > > > thing I noticed was that my post was poorly worded. Let me
> > reword it
> > > > > below, and maybe you can tell me if this is what you
> thought I
> > > > meant....
> > > > >
> > > > > Ok. It's easy to find the first occurrence of a true value
> of an
> > > > > array... that is looking from now backwards x intervals.
> simply
> > > > > HHV(array,x) where x=no of intervals back.
> > > > >
> > > > > However, how can I find the last true value of the array
> looking
> > > > back
> > > > > over x intervals...?? i.e. the first true value starting
from
> > x and
> > > > > looking forward to now.
> > > > >
> > > > > is there an array method without looping...?
> > > > >
> > > > > Many Thanks
> > > > >
> > > > >
> > > > > --- In amibroker@xxxxxxxxxxxxxxx, Graham <kavemanperth@>
> wrote:
> > > > > >
> > > > > > try this
> > > > > > array = h;
> > > > > > LastHHVValue = valuewhen( hhvbars(array,x)==0, array );
> > > > > >
> > > > > > --
> > > > > > Cheers
> > > > > > Graham Kav
> > > > > > AFL Writing Service
> > > > > > http://www.aflwriting.com
> > > > > >
> > > > > >
> > > > > >
> > > > > > 2009/1/13 sidhartha70 <sidhartha70@>:
> > > > > > > Hi All,
> > > > > > >
> > > > > > > Ok. It's easy to find the last true value of an array...
> > simply
> > > > > > > HHV(array,x) where x=no of intervals back.
> > > > > > >
> > > > > > > However, how can I find the last true value of the
array
> > > > looking back
> > > > > > > over x intervals...??
> > > > > > >
> > > > > > > is there an array method without looping...?
> > > > > > >
> > > > > > > Many Thanks
> > > > > > >
> > > > > > >
> > > > > >
> > > > >
> > > >
> > >
> > >
> > >
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