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How about this?
x = condition that generates your 1,0
array
y = sum(x, range)
z = valuewhen(x, barindex(), y)
position in array = lastvalue(barindex()) - z +
1
Bill
----- Original Message -----
Sent: Monday, January 12, 2009 6:33
PM
Subject: [amibroker] Re: Finding the last
true value in an array...
Sorry Barry... my terminology is confusing...
Lets say I
have an array that has only true or false values in it...
Lets say the
last 10 value of this array are as follows, from x
intervals ago until
now...
0,1,0,0,1,0,0,1,0,0
x.................Now
Now,
obviously, BarsSince(array) will return a value of 2... i.e. the
last true
value was 2 intervals ago.
However, the value I'm trying to get is the
last value of true in the
above x elements of the array... so I want an
_expression_ that returns
8 for the above array (i.e. 8 intervals back is the
last value of
true). Any ideas...?
Hopefully that's clearer
now.
--- In amibroker@xxxxxxxxxxxxxxx, "Barry
Scarborough" <razzbarry@xxx>
wrote:
>
> What are your
trying to do? HHV gives the value of the highest high
> over the period
you enter in x. If you want to find how far back that
> is you can use
>
> bs = BarsSince(H == HHV(H, 10));
> // the next line
prints the num bars back and the high of that bar
> printf(NumToStr(bs,
1.0) + " High " + NumToStr(HHV(H, 10), 1.2));
>
> If you want to
find the value of the other things bs bars ago then
> you can
>
// use the following. This applies to any array
> lastHigh = ref(High,
- bs);
> // this is another way to see the results that shows the high
value
> Plot(lastHigh, "high bars ago", colorBlack);
> Plot(Ref(C,
-bs), "close bars ago", colorblue);
> Plot(Ref(MA(C, 10), -bs), "MA(10)
value bars ago", colorGreen);
> // then look at what valuewhen
returns
> Plot(ValueWhen(H == HHV(H, 10), H, -1), "ValueWhen",
colorRed);
>
> bsolutely the last thing you want to do is start
using loops, such as
> for loops, to extract data from ABs arrays. Your
code will be much
> cleaner and faster if you use straight AFL.
>
> Your terminology true value is confusing. The value in an array is
> the true value. Do you mean what was the value when the condition was
> true?
>
> Barry
>
>
>
>
--- In amibroker@xxxxxxxxxxxxxxx,
"sidhartha70" <sidhartha70@>
> wrote:
> >
> >
Graham,
> >
> > I'm trying to get my head around that code
right now... but first
> > thing I noticed was that my post was
poorly worded. Let me reword it
> > below, and maybe you can tell me
if this is what you thought I
> meant....
> >
> >
Ok. It's easy to find the first occurrence of a true value of an
> >
array... that is looking from now backwards x intervals. simply
> >
HHV(array,x) where x=no of intervals back.
> >
> > However,
how can I find the last true value of the array looking
> back
>
> over x intervals...?? i.e. the first true value starting from x
and
> > looking forward to now.
> >
> > is there
an array method without looping...?
> >
> > Many
Thanks
> >
> >
> > --- In amibroker@xxxxxxxxxxxxxxx, Graham
<kavemanperth@> wrote:
> > >
> > > try
this
> > > array = h;
> > > LastHHVValue = valuewhen(
hhvbars(array,x)==0, array );
> > >
> > > --
>
> > Cheers
> > > Graham Kav
> > > AFL Writing
Service
> > > http://www.aflwriting.com
> >
>
> > >
> > >
> > > 2009/1/13
sidhartha70 <sidhartha70@>:
> > > > Hi All,
> >
> >
> > > > Ok. It's easy to find the last true value of
an array... simply
> > > > HHV(array,x) where x=no of intervals
back.
> > > >
> > > > However, how can I find
the last true value of the array
> looking back
> > > >
over x intervals...??
> > > >
> > > > is there
an array method without looping...?
> > > >
> > >
> Many Thanks
> > > >
> > > >
> >
>
>
>
>
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