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Re: [amibroker] Re: Consistent coding structure problem



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The only error I got was "ABC_check" was not initialized.  After fixing that, it ran without error.


On Thu, Nov 6, 2008 at 12:44 PM, sidhartha70 <sidhartha70@xxxxxxxxx> wrote:

Sorry... let me repost that code...



HLRange = abs( H - L );
ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2) AND
HLRange > Ref( HLRange, -3 );
XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));

if(XYZ_Check==0)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==1)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==2)
{
printf("XYZ_Check = " + XYZ_Check);
}
if(XYZ_Check==3)
{
printf("XYZ_Check = " + XYZ_Check);

}

--- In amibroker@xxxxxxxxxxxxxxx, "sidhartha70" <sidhartha70@xxx> wrote:
>
> Hi All,
>
> I keep running into a consistent coding structure problem,
>
> HLRange = abs( H - L );
> ABC = HLRange > Ref( HLRange, -1 ) AND HLRange > Ref( HLRange, -2 )
> AND HLRange > Ref( HLRange, -3 );
> XYZ_Check=IIf(Ref(ABC,-1),1,IIf(Ref(ABC,-2),2,IIf(Ref(ABC,-3),3,0)));
>
> if(ABC_Check==0)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==1)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==2)
> {
> printf("ABC_Check = " + ABC_Check);
> }
> if(ABC_Check==3)
> {
> printf("ABC_Check = " + ABC_Check);
> }
>
> Obviously I keep getting Error 6 stating that in the 'if(_expression_)'
> statements _expression_ cannot be an array.
> This raises a more generic question... is there a way of programming
> structures like these WITHOUT having to resort to using loops....?
>
> Any ideas appreciated.
>
> TIA
>


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