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[amibroker] Re: BarCount of FirstBarIntest



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Try wrapping the expressions in a call to LastValue.

e.g.
LastValue(ValueWhen( Status( "FirstBarInTest" ), BarIndex() );

Mike

--- In amibroker@xxxxxxxxxxxxxxx, "tipequity" <l3456@xxx> wrote:
>
> 
> Thanks Steve for your quick response. For some reason it is gives an
> error message:
> 
> Error6, COndiftion inIF, WHILE, FOR statements has to Numeric or 
Boolean
> type. You can not use array here....
> 
> 
> 
> --- In amibroker@xxxxxxxxxxxxxxx, "Steve Dugas" <sjdugas@> wrote:
> >
> > How about something like this....
> >
> > FirstBar = ValueWhen( Status( "FirstBarInTest" ), BarIndex() );
> > LastBar = ValueWhen( Status( "LastBarInTest" ), BarIndex() );
> > for ( i = FirstBar; i <= LastBar; i++ )
> > ...
> >
> > Steve
> >
> > ----- Original Message -----
> > From: "tipequity" l3456@
> > To: amibroker@xxxxxxxxxxxxxxx
> > Sent: Sunday, July 06, 2008 10:49 PM
> > Subject: [amibroker] BarCount of FirstBarIntest
> >
> >
> > >I am trying to back test a system. I want to start my loop from
> > > i=FirstBarIntest to LastBarInTest. It that possible? if so how?
> > >
> > > if (Status("action") == 5) // Backtest
> > > {
> > > for ( i =1 ; i < BarCount; i++ )
> > > {
> > > if (BuySignal[i])
> > > {
> > > Buy[i] = 1 ;
> > > CategoryAddSymbol("", categoryWatchlist, 61);
> > > }
> > > if (SellSignal[i] AND InWatchList(61) )
> > > {
> > > Sell[i] = 1;
> > > }
> > > }
> > > }
> > >
> > >
> > > ------------------------------------
> > >
> > > Please note that this group is for discussion between users 
only.
> > >
> > > To get support from AmiBroker please send an e-mail directly to
> > > SUPPORT {at} amibroker.com
> > >
> > > For NEW RELEASE ANNOUNCEMENTS and other news always check 
DEVLOG:
> > > http://www.amibroker.com/devlog/
> > >
> > > For other support material please check also:
> > > http://www.amibroker.com/support.html
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> >
>



------------------------------------

Please note that this group is for discussion between users only.

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