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Chorlton,
You are correct in that the IIF statement is not needed. Any IIF
statement in which the two possible results are just 1 and 0 can be
done the way you suggest.
AND and NOT are two independant logical operations. AND means both 'x'
and the next part, while NOT just negates the result of the statement
following it. Where that's not a comparison operation, it means if the
result is zero.
So that second line says the number of bars since 'x' was non-zero and
the previous value of 'x' was zero.
GP
--- In amibroker@xxxxxxxxxxxxxxx, "chorlton_c_hardy"
<chorlton-c-hardy@xxx> wrote:
>
> x = iif(h == hhv(h, 30), 1, 0);
> y = barssince(x and not ref(x,-1));
>
> As a non-programmer, can someone explain the 2 lines of code in plain
> english?
>
> If I correctly understand it, the 1st line will return a 1 if the
> argument h==hhv(h,30) is true and a 0 if it isn't. However, what
> confuses me is why the iif statement is needed in the first place.
> Shouldn't the 1st line simply say x = h == hhv(h, 30)?
>
> Also, what does "and not ref(x,-1))" mean in the 2nd line?
>
> Apologies for the very basic question...
>
>
>
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Mike Lucero" <m.lucero@> wrote:
> >
> > For just the initial breakout:
> >
> > x = iif(h == hhv(h, 30), 1, 0);
> > y = barssince(x and not ref(x,-1));
> > ----- Original Message -----
> > From: wavemechanic
> > To: amibroker@xxxxxxxxxxxxxxx
> > Sent: Thursday, November 08, 2007 9:30 AM
> > Subject: Re: [amibroker] Re: Help with some Coding
> >
> >
> > "Calculate the number of Bars (x) since the HHV of the High over
> the last 30 periods."
> >
> > x = iif(h == hhv(h, 30), 1, 0);
> > y = barssince(x);
> >
> > Bill
> >
> >
> > ----- Original Message -----
> > From: "chorlton_c_hardy" <chorlton-c-hardy@>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Thursday, November 08, 2007 8:18 AM
> > Subject: [amibroker] Re: Help with some Coding
> >
> >
> > >
> > > Hi Ton,
> > >
> > > I can see why it sounds confusing....
> > >
> > > Basically, I don't want condition 1 to be met if the price simply
> > > breaks all time highs.
> > >
> > > Instead, Once we have the HHV of the High over the last 30
> periods, I
> > > then want price to retrace back down and then rise again and
> finally
> > > break out (ie. Cross the HHV of the previous 30 periods). Only at
> > > this point do I want condition 1 to be met!
> > >
> > > Is this any clearer? :-/
> > >
> > > If it isn't, then for this exercise in regard to coding, I can
> change
> > > condition 1 to:
> > >
> > > 1: Calculate the number of Bars (x) since the HHV of the High
> over
> > > the last 30 periods.
> > >
> > >
> > > All the best....
> > >
> > >
> > > --- In amibroker@xxxxxxxxxxxxxxx, "Ton Sieverding"
> > > <ton.sieverding@> wrote:
> > >>
> > >> I am probably missing something in your logical problem
> definition,
> > > Chorlton. When I am taking the highest high over a certain
> period,
> > > how can I get a high during this period that will be higher ?
> > >>
> > >> Regards, Ton.
> > >>
> > >>
> > >> ----- Original Message -----
> > >> From: chorlton_c_hardy
> > >> To: amibroker@xxxxxxxxxxxxxxx
> > >> Sent: Thursday, November 08, 2007 1:01 PM
> > >> Subject: [amibroker] Help with some Coding
> > >>
> > >>
> > >> Hello All,
> > >>
> > >> I want to code the following conditions and would welcome some
> > > help.
> > >> I've included my attempt of the code but would appreciate
> > > comments as
> > >> to whether this is an accurate translation into AB code.
> > >>
> > >> Conditions:
> > >>
> > >> 1: Calculate the number of Bars (x) since the last time High
> > > crossed
> > >> above the HHV of the High over the last 30 periods.
> > >> 2. The value of RSI(14) x periods ago should be more than the
> > > current
> > >> value of RSI(14)
> > >>
> > >> eg. If the output from condition 1 was say 8, then condition 2
> > > would
> > >> be RSI(14)>Ref(RSI(14),-8)
> > >>
> > >> My attempt at the Code:
> > >>
> > >> x:=BarsSince(Cross(H,Ref(HHV(H,30),-1)));
> > >> RSI(14)> Ref(RSI(14),x*-1)
> > >>
> > >> Would this work?
> > >>
> > >> Thanks in advance,
> > >>
> > >> Chorlton
> > >>
> > >
> > >
> > >
> > >
> > > Please note that this group is for discussion between users only.
> > >
> > > To get support from AmiBroker please send an e-mail directly to
> > > SUPPORT {at} amibroker.com
> > >
> > > For NEW RELEASE ANNOUNCEMENTS and other news always check DEVLOG:
> > > http://www.amibroker.com/devlog/
> > >
> > > For other support material please check also:
> > > http://www.amibroker.com/support.html
> > >
> > > Yahoo! Groups Links
> > >
> > >
> > >
> > >
> > >
> > > --
> > > No virus found in this incoming message.
> > > Checked by AVG Free Edition.
> > > Version: 7.5.503 / Virus Database: 269.15.22/1112 - Release Date:
> 11/5/2007 7:11 PM
> > >
> > >
> >
>
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