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Thanks
I don't know why I try to complicate things.
Rick
--- Graham <kavemanperth@xxxxxxxxx> wrote:
> have you tried a simpler method?
>
> array = RSI(21);
> Threshold = 50;
> count = barssince(array>=threshold);
>
> --
> Cheers
> Graham Kav
> AFL Writing Service
> http://www.aflwriting.com
>
>
>
> On 27/09/2007, Rick Osborn <ricko@xxxxxxxxxx> wrote:
> > You are correct (typo) - but fixing that doesn't
> solve
> > my initial problem
> >
> > --- Ara Kaloustian <ara1@xxxxxxxxxx> wrote:
> >
> > > Seem to be missing a ";" after "count = 0".
> > >
> > > You should be getting an error message.
> > >
> > > ----- Original Message -----
> > > From: "ricko8294_98" <ricko@xxxxxxxxxx>
> > > To: <amibroker@xxxxxxxxxxxxxxx>
> > > Sent: Wednesday, September 26, 2007 7:34 PM
> > > Subject: [amibroker] Loop Problem
> > >
> > >
> > > > What is wrong with this code? The concept
> seems
> > > to simple and it's
> > > > driving me nuts.
> > > >
> > > > I want to count the number of consecutive days
> an
> > > array, (say RSI(21)
> > > > is above a threshhold, (say 50) but to revert
> to
> > > zero if it falls
> > > > below that threshhold.
> > > >
> > > > Here is the code, which does not seem to work.
> > > The value of "Count"
> > > > always seems to be zero.
> > > >
> > > >
> > > >
> > > > array = RSI(21);
> > > > Threshold = 50;
> > > > ConsecutiveDays = 10;
> > > > Count = 0 // initialize
> > > >
> > > > for (i = 1; i < ConsecutiveDays + 1; i++)
> > > > {
> > > >
> > > > if (Array[i] >= Threshold[i]) Count[i] =
> > > Count[i-1] + 1;
> > > >
> > > > else Count[i] = 0;
> > > > }
> > > >
> > > >
> > > > Thanks
> > > > Rick
>
Rick Osborn
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