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Read the manual:
http://www.amibroker.com/guide/h_understandafl.html
http://www.amibroker.com/guide/a_mistakes.html
Best regards,
Tomasz Janeczko
amibroker.com
----- Original Message -----
From: "lifes_student_1" <suedeuno@xxxxxxxxx>
To: <amibroker@xxxxxxxxxxxxxxx>
Sent: Saturday, August 25, 2007 9:29 PM
Subject: [amibroker] Re: getting an error in my if statement
> Thanks. Why can't I do the following though that should result in a
> boolean:
>
> color = colorLime;
> color2 = colorRed;
> i1 = colorLime;
> c1 = ((i1 == color OR i1 == color2));
> if (c1 == true)
> {...
>
>
> This doesn't work. I guess I'm not used to AFL.
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Thomas Z." <tzg@xxx> wrote:
>>
>> You need a loop and then you could write if(barsback[i] < 6)
>>
>> The other way would be to use IIF()
>>
>> Regards
>> Thomas
>> www.patternexplorer.com
>>
>>
>>
>> From: amibroker@xxxxxxxxxxxxxxx [mailto:amibroker@xxxxxxxxxxxxxxx]
> On Behalf
>> Of lifes_student_1
>> Sent: Saturday, August 25, 2007 8:28 PM
>> To: amibroker@xxxxxxxxxxxxxxx
>> Subject: [amibroker] getting an error in my if statement
>>
>> condition1 = cross(close, ma(close,20));
>> barsback = BarsSince(condition1 == true);
>> if(barsback < 6)
>> {...
>>
>> I'm getting error 6 on barsback in if statement. condition1 is set
> and
>> works as I've tested it elsewhere. What am I doing wrong?
>>
>> (Condition in IF, WHILE, FOR statements has to be Numeric or
> Boolean
>> type. You cannot use an array here....)
>>
>
>
>
>
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Please note that this group is for discussion between users only.
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