Hello,
You must not assume that you have some fixed number of
data elements available. *Always* perform a check for BarCount.
So instead of:
for (i = 0; i < 10; i++) myArr[i] = 0;
always include check:
for (i = 0; i < 10 AND i < BarCount; i++) myArr[i] = 0;
alternatively:
if( BarCount >= 10 )
{
..... put code that assumes that you have 10 data points available here.
}
Best regards,
Tomasz Janeczko
amibroker.com
----- Original Message -----
From: "gp_sydney" <
gp.investment@gmail.com>
To: <
amibroker@xxxxxxxxxps.com>
Sent: Saturday, June 16, 2007 2:08 AM
Subject: [amibroker] Re: New file uploaded to amibroker
> > I still do not understand what the difference between the size of an
> > array and the number of elements in an array is.
>
> They are the same, but when you have a loop
writing only 10 elements
> to an array, that's not how many elements are in the array, it's only
> the number of elements you've changed. The array might have 1000
> elements and all you've done is overwrite the first 10.
>
> The size of an array is how many elements it's physically possible to
> change because there's actually memory allocated for their storage. In
> AmiBroker that's always BarCount.
>
> As I sort-of mentioned before, using arrays where the index is
> something other than bars, and you fix the range of the index to
> something other than BarCount, can easily lead to problems. If you
> have such a formula in a backtest and run that across all symbols, the
> moment you hit a symbol where BarCount is less than the maximum index
> you use, you'll get an overflow error.
>
> For example, if you have the following code in a backtest:
>
> for (i = 0; i
< 10; i++) myArr[i] = 0;
>
> and run it over all symbols, if you hit a new listing that only has
> five bars on the chart then you'll get an overflow error when myArr[5]
> is referenced for that symbol.
>
> Regards,
> GP
>
>
>
>
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