If we are talking OUTSIDE of AB / AFL like in vbs etc ... yes it
does.
Inside AFL it essentially does the same thing as well ...
However,
you would also by default have available elements 12 i.e. [11]
through the number of bars in the charted security. The simple way
to
think of this is that AB is providing the DIMENSION statement for
you and
it will contain the same number of elements that are in the
charted
security and it will be aligned to the charted security.
Hwever you can
use whatever elements of the array you want ... If for
some reason that's
only 1 through 10 then so be it.
--- In amibroker@xxxxxxxxxps.com,
"Ton Sieverding"
<ton.sieverding@...> wrote:
>
>
Correct about 11 elements of course. Quickie. Sorry for that. But I
still
do not understand what the difference between the size of an
array and the
number of elements in an array is. Forget AFL for a
moment. When I create
an array with one of the popular statements
like DIMENSION MyArray(10)
does not give me this the same result as
underneath mentioned For Loop ? I
am probably missing something ...
>
> Regards, Ton.
>
> ----- Original Message -----
> From: gp_sydney
> To: amibroker@xxxxxxxxxps.com
> Sent: Friday, June 15, 2007 12:04 PM
> Subject: [amibroker] Re:
New file uploaded to amibroker
>
>
> > Isn't this the
same as creating an array with 10 elements ?
> > for (i = 0 ; i <
11; i++) MyArray[i] = 0;
>
> No, ignoring the fact it's actually
11 elements (ie. 0-10). That's
> just filling the first 11 elements of
the array, it doesn't
define the
> size of the array. If you tried
that on a chart that only had five
> bars, you'd get an array overflow
error.
>
> > How about two dimensional arrays ?
>
> AFL doesn't directly have two-dimensional arrays, but I did
see
> something on the AB site once about effectively creating them
using
> the VarSet and VarGet functions. Looked pretty messy
though.
>
> GP
>