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Thanks Herman. I know that in programmers land there are a thousand possible ways to Rome. I even can put all the to do's in a function and then call the function from within the IIF etc. etc. But that's not how it should be programmed and that's not my question. I just don't know the syntax of the double IIF in AFL and would like to know that. The frustrating thing for me is that I cannot find it in the AFL manual. Don't forget that in AFL the double IIF has a special function. It made to handle arrays. So there is no need for a loop ...
Ton.
----- Original Message -----
From: Herman
To: amsiev
Sent: Wednesday, February 14, 2007 7:23 PM
Subject: Re: [amibroker] AFL syntax for nested IIF ?
Not sure what you are trying to do but often using a loop may simplify things:
FirstVisibleBar = Status( "FirstVisibleBar" );
Lastvisiblebar = Status("LastVisibleBar");
for( b = Firstvisiblebar; b < Lastvisiblebar AND b < BarCount; b++)
{
if( BarNumAct[b] <= 21 )
{
Highs[b] = C[b];
Lows[b] = C[b];
Range[b] = (H[b] - L[b])/2;
}
}
herman
Wednesday, February 14, 2007, 12:39:24 PM, you wrote:
> What's the syntax in AFL for a double IF with following structure ?
> IF True
> Do This ;
> Do That ;
> Do anything;
> Endif
> I'm working with arrays so I must use the double IF but my problem is
> that I just cannot get the correct syntax. There are in fact two
> problemens. First I only want the IIF to do something when the
> condition is true. Therefore I don't want the third part in case the
> IIF is false or the 'Do if false'. Second I want the IIF to do
> several things. Not just one. Following syntax is wrong. So what's
> the correct one ?
> IIf(BarNumAct<=21,
> {
> Highs[BarNumAct] = Close;
> Lows[BarNumAct] = Close;
> Range[BarNumAct] = (High - Low)/2;
> }
> ,"");
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