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Hi, thanks a lot for your help! It seems to work like that, thanks!
Haven't succeeded to run this because I don't seem to get my if-
statements correct either. The error message i get is "Error 6.
Condition in IF, WHILE, FOR statements has to be Numeric or Boolean
type. You can not use array here, please use [] (array subscript
operator) to access array elements".. :(
Hopefully someone can solve this for me, I tried to do it in two ways
but haven't really got it right.. :(
/********CODE Snippet
//Averages of three HHVs and LLVs
HHavg=(HHA+HHB+HHC/3);
LLavg=(LLA+LLB+LLC/3);
//Calculate 5% of HHV, both 5% more and 5% less
HHmin=(HHV(H,30) * 0.95);
HHmax=(HHV(H,30) * 1.05);
LLmin=(LLV(L,30) * 0.95);
LLmax=(LLV(L,30) * 1.05);
//Now check to see if the averages of the three HHVs and
//LLVs are not deviating too much from the min and max values,
//I chose 5% as example of maximum deviation.
//HHAvg is between HHV - 5% and HHV + 5%
//LLAvg is between LLV - 5% and LLV + 5%
//I tried to make this like a nested if-statement
//HChannel is set as False to begin with...
HChannel=False;
if (HHavg > HHmin) {
if (HHavg < HHmax) {
if (LLavg > LLmin) {
if (LLavg < LLmax) {
hChannel=True; }
} } }
//Finally the filter for the exploration
Filter=hChannel=True;
--- In amibroker@xxxxxxxxxxxxxxx, "wlandry01" <wlandry01@xxx> wrote:
>
> Hi,
>
> I believe that you have included one too many arguments for "HHV".
> Are you trying to use "Ref" with "HHV"? You can use the following
> simple code to see if this helps:
>
> HHB=Ref(HHV(C,10),-10);
> AddColumn(C,"Close",1.2);
> AddColumn(Htest,"Htest",1.2);
> Filter=1;
>
> I don't know if this will get you where you are trying to go or not
> but the syntax does appear to be a problem. Others who are much
more
> familiar with AFL will, no doubt, be able to provide more insight.
>
> I would also check the AFL library as I seem to recall seeing some
> examples that address channels. TJ has some code there that deals
> with troughs and peaks, which is somewhat related to your subject.
He
> has some excellent commentary included in the listing that you might
> find interesting and helpful:
>
> http://www.amibroker.com/library/detail.php?id=19
>
>
> Wayne
>
>
>
> --- In amibroker@xxxxxxxxxxxxxxx, "carlacash26" <carlacash26@>
wrote:
> >
> > I want to plot a horizontal line from the Highest High Value and
one
> > from the Lowest Low Value for the past 30 days. In addition to
this I
> > want to have an exploration find stocks where the price has
turned in
> > the proximity of this line (support/resistance) over the past 30
days
> > (or any period that I define). In other words I want to search
for a
> > horizontal channel that has lasted for past 30* days.
> >
> > I have thought about how to implement this and maybe this is a
> > suitable way?..:
> >
> > To find the the HHV for the last 10 days, AND the HHV for the
last 10
> > to 20 days, AND the HHV for the last 20 to 30 days.
> > And then the same thing for the LLV. Do you understand what I
mean?
> >
> > Then if the HHV/LLV for these timeperiods don't deviate from each
> > other that much, then I can assume that there is
resistance/support
> > for past 30 days at this level. I could divide the range into
> > more/less timeperiods also, I don't know the best number of
periods,
> > I chose 3 to begin with.
> >
> > What do you think about this approach? Do you find anything that
> > don't make sense about this?
> >
> >
> > /***************************************************************/
> > //THE CODE I HAVE COME UP WITH,
> > //it's not finished by any means but you get my point hopefully
> > //The syntax is probably not correct, this is some kind
> > //of pseudo code I guess, I have just written this in notepad
> > /***************************************************************/
> >
> >
> > // First find the highest high values, And lowest low values for
the
> > 3 periods; 10 days ago, 10-20 days ago, and 20-30 days ago
> >
> > HHA=HHV(H,10,-1); //HHV of 10 days ago (for example 33)
> > HHB=HHV(H,10,-10); //HHV of 10 to 20 ago (for example 32)
> > HHC=HHV(H,10,-20); //HHV of 20 to 30 days ago (for example 34)
> >
> > LLA=LLV(L,10,-1); //LLV of 10 days ago (for example 27)
> > LLB=LLV(L,10,-10); //LLV of 10 to 20 ago (for example 28)
> > LLC=LLV(L,10,-20); //LLV of 20 to 30 days ago (for example 29)
> >
> >
> >
> > //Then caluculate the average of these HHVs and LLVs
> >
> > HHavg=(HHA+HHB+HHC/3);//(for example = 33)
> > LLavg=(LLA+LLB+LLC/3); //(for example =28)
> >
> >
> >
> > //Then check to see if the averages of the three HHVs and
> > //LLVs are not deviating too much, I chose 5% as example
> > //of maximum deviation.
> >
> >
> > //HHAvg is between HHV - 5% and HHV + 5%
> > if ((HHavg > (HHV(H,30) * 0.95)) AND (HHavg < (HHV(H,30) *
1.05)))
> >
> > AND
> >
> > //LLAvg is between LLV - 5% and LLV + 5%
> > if ((LLavg > (LLV(L,30) * 0.95)) AND (LLavg < (LLV(L,30) *
1.05)))
> >
> > { hChannel=TRUE; }
> > //if they don't differ more than 5% there is a horizontal channel
> >
> >
> > Filter=hChannel; //filter for stocks where hchannel is true
> >
> > //now plot the channel for stocks where hChannel=true
> > //i.e. plot lines from HHavg and LLavg, AND plot lines
> > //from HHV(H,30,-1) and LLV(L,30,-1)
> > //then maybe explore stocks that break out of these
> > //resistance levels. Haven't thought about this yet...
> >
> > //Code ends here
> >
> >
> > Please could you give your opinion on this, I might have missed
> > something or maybe I'm completely off track? Is there a better
way
> > to find horizontal support and resistance that I could use to
find
> > horizontal channels/ranges?
> >
> > Thank you very much for any help or suggestions or comments you
can
> > give! It's highly appreciated!
> >
>
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Checked by AVG Free Edition.
Version: 7.5.432 / Virus Database: 268.17.31/676 - Release Date: 2/8/2007 3:04 PM
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