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1e10 = 10,000,000,000
--
Cheers
Graham
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On 31/10/06, Vins <mrpurple@xxxxxxxx> wrote:
>
> i can also put to 0 (zero) the stop, and than change the vakue of
> trailing stop.
> 0,2,10 i belive that was the type of stop, the mode, and the ammount
> as i found in the function reference.
> do you have a link to learn in use constants ? 1e10 it means
> 0.0000000001 to be almost to 0 ?
> i hope to don't have done too much stupid question.
> thank You
>
> --- In amibroker@xxxxxxxxxxxxxxx, "Tomasz Janeczko" <groups@xxx>
> wrote:
> >
> > As error says you can have "type" or "mode" params as array
> >
> > Only the "Amount" may be array.
> >
> > If you want to turn stop on/off you should simply modify AMOUNT
> > so it is very high when you turn it OFF"
> >
> > And learn using constants to make your code readable
> > because 0,2,10 does not tell anything
> >
> > TrStopOn = ...
> > ApplyStop( stopTypeTrailing, stopModePercent, IIf( TrStopOn == 1,
> 6, 1e10 ) );
> > ApplyStop( stopTypeLoss, stopModePercent, IIf( TrStopOn == 1, 1e10,
> 10 ) );
> >
> >
> > Best regards,
> > Tomasz Janeczko
> > amibroker.com
> > ----- Original Message -----
> > From: "Vins" <mrpurple@xxx>
> > To: <amibroker@xxxxxxxxxxxxxxx>
> > Sent: Sunday, October 29, 2006 11:37 PM
> > Subject: [amibroker] from a stop switching in a trailing stop
> >
> >
> > > hi,
> > > this is a formula for a stop
> > > ApplyStop(0,2,10,1,False));
> > >
> > > here the trailing stop
> > > ApplyStop(2,2,6,1,False);
> > >
> > > so now i'ld like to put the stop but if a condition is verified
> > > switchin in trailing stop
> > >
> > > i wrote this
> > > trstopon= condition;
> > > ApplyStop(IIf(trstopon==1,2,0),2,IIf(trstopon==1,6,10),1,False);
> > >
> > > but i'm getting an error and cursor blinking after FALSE.
> > > from the help of error:
> > > "Error 4. Incorrect type of argument(s). Expecting number here.
> > > This occurs in ApplyStop function when Type, Mode, ExitAtStop or
> > > Volatile parameter is an array"
> > >
> > > thank You
> > >
>
>
>
>
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