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Since I can't see the rest of your code I'm not sure why you wanted
this to be in a loop but if all you are interested in is the number
of 1's and 0's there are in some array looking backwards for n ( in
this case 10 ) bars then this can be done without a loop by for
example ...
// Generate an array with 1's and 0's
OnesZeros = IIf(C > Ref(C, -1), 1, 0);
Ones = Sum(OnesZeros, 10);
Zeros = Sum(OnesZeros == 0, 10);
Filter = 1;
AddColumn(OnesZeros, "1 / 0");
AddColumn(Ones, "1's");
AddColumn(Zeros, "0's");
--- In amibroker@xxxxxxxxxxxxxxx, John Nelson <trader@xxx> wrote:
>
>
> All,
>
> I'm counting the number of 1's and 0's from arrays which are the
results
> of our well-known set of indicators. The 1's and 0's actually
represent
> peaks and valleys and I'd like an indication of how many of them
there
> are within a specific period starting from the current bar and
going back
> myPeriod bars. I've noticed something strange though.
>
> If I try to count in this manner....
>
> for ( i = 0; i < myPeriod; i++ ) {
> if ( myarray[i] == 1 )
> total1 = total1 + 1;
> else
> total2 = total2 + 1;
> }
>
> I stumble across a runtime error that admonishes me for having a
subscript
> that is not between 0 ... (BarCount-1). However the following
snippet of
> code avoids the runtime error...
>
> for ( i = 0; i < BarCount && i < myPeriod; i++ )
{
> if ( myarray[i] ==
1 )
> total1 = total1 +
1;
>
else
> total2 = total2 +
1;
> }
>
> Now this is really strange since I know "myPeriod" is far less
than the
> BarCount. Could it be that AFL operations aren't striclty linear
in that
> the results of my array operations preceeding the for loop are not
yet
> complete? Could it be that I don't understand how array subscripts
work?
>
> So what is the proper way to count the number of 1's and 0's in an
array
> starting from the most recent bar and working back?
>
> -- John
>
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