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mytime = timenum()==170000; If 170000 does not always appear then you
may need to use Cross(timenum(),170000) or Cross(timenum(),165959)
check against your bar timing set up in preferences
Assuming the period closes at 170000 and opened at previous 170001
then you could use something along these lines. Just do some testing
to check my syntax and logic is correct
mytime = timenum()==170000;
PeriodHigh = valuewhen( mytime, ref(highestsince( mytime, H ),-1) );
PeriodClose = valuewhen( mytime, c );
PeriodOpen = valuewhen( mytime, ref(O,1), 2 );
PeriodLow = valuewhen( mytime, ref(lowestsince( mytime, L ),-1) );
remember this is just one way to do things, and may not be the best or
the most recent method available, just one that comes to mind as
typing.
On 8/6/05, Steve <avalon-ardy@xxxxxxxxxxxxxxx> wrote:
> Is it possible to calulate pivots based on a timeframe that spans 2 days?
> ie. calculate H,L,C from say 17.00 yesterday till 17.00 today. If so, any
> pointers?
> I've experimented with Timenum() but it is only good for current 24hr
> period & I'm not sure how to use it to reference a previous 24hr period. And
> I don't think the TimeFrameGetPrice() can be used in this instance either.
> Thanks!
>
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--
Cheers
Graham
AB-Write >< Professional AFL Writing Service
Yes, I write AFL code to your requirements
http://e-wire.net.au/~eb_kavan/ab_write.htm
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