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in AFL looping, or if you use script then you define the array using [i] addons.
In script you also need to define the variables within the script
before you use them.`
so for an array
XYZ = C[0]; would define it as an array
XYX = 0; would define it as zero unless given another value within the
loop script.
On 7/8/05, Joe Landry <jelandry@xxxxxxxxxxxxx> wrote:
> Someone asked earlier about why I had used the expression
> Count = Close-Close;
> in initializing my arrays to zero and I found out from my tutor
> this morning why I had been taught that convention.
>
> Most of the time you will not get into any issues if you write
>
> Count = 0;
>
> rather than
>
> Count = Close - Close; or Count = C-C;
>
> However if you call or exit to VBscript or potentially jScript utilities in
> the same AFL module,
> the script functions don't know in what context you used Count = 0; i.e.
> was it a scalar you
> are passing or an array(vector) as a parameter; but if you initialize it as
> an array there will be no doubt.
>
> An example would be if you call a VB utility and use the variable count as a
> parameter
> without defining it as an array you could get some wierd errors, for
> example if you
> tried to intierate count[i] inside the VB script you probably would get a
> surpise.
>
> The flexibility of AFL is great in that it doesn't require you to define
> arrays and scalars,
> it figures in what context you used it for the most part without any
> hickups. There have
> been many versions of AB since that convention was adopted but it doesn't
> take much
> time to TYPE your variable as an array.
>
> I'll be happy to stand corrected by someone knowegable in programming and
> AFL
> if I didn't represent this correctly. Let me know.
>
> Hope this helps.
> JOE
>
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--
Cheers
Graham
http://e-wire.net.au/~eb_kavan/
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