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I tried looking at your code and coudln' figure out why AB was
thinking i or n were arrays and not just single numbers.
Having said that... I think you might be able to achiece what you want
without loops. Take a look at this and let me know if this is waht
you are looking for.
Also, how are you using this?
----------start-----------
Lookback = 100;
Runup=HHV(BarsSince(Cross(C, Ref(C, -1))) * (C > Ref(C,-1))+1, Lookback );
Rundown=HHV(BarsSince(Cross(Ref(C, -1), C)) * (Ref(C,-1) > C)+1,
Lookback );
Plot(Runup,"Max Runup", colorGreen, styleLine);
Plot(rundown,"Max Rundown", colorRed, styleLine);
----------end-------------
--- In amibroker@xxxxxxxxxxxxxxx, "liugq_99" <gliu@xxxx> wrote:
>
> Hi,
>
> A maximum run is defined as the maximum number of days (daily data)
> consecutive runing up or running down for a certain time of period.
> For example, a 100 day maximum run being 5 means the maximum number
> of days consecutively running up (or down) is 5.
>
> I need a help to write a AFL code for this. Thanks.
>
> liugq_99
>
> My AFL code below has a "if" error:
>
>
> r=log(C/Ref(C,-1));
> n=100; //n--period
>
> i=0;
> arun=1;
> brun=1;
> do
> {
> x=IIf(Ref(r,-i)>0,1,0);
> y=IIf(Ref(r,-i-1)>0,1,0);
> t=IIf(x-y=0,1,0);
> arun=arun+t;
> maxr=Max(arun,brun);
> brun=maxr;
> if(t==0) arun=1;
> i=i+1;} while (i<n);
>
> Plot(brun,"",1,1);
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